Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option
Explanation:
Let the speed of the second train be x km/hr.
| Relative speed | = (x + 50) km/hr | |||||||
|
||||||||
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![]](/_files/images/aptitude/1-sym-cbracket-h1.gif)
Distance covered = (108 + 112) = 220 m.
 |
220 | = 6 | ||
|
250 + 5x = 660
x = 82 km/hr.
Discussion:
77 comments Page 5 of 8.
Apoorv said:
9 years ago
Sir, if the train is moving in an opposite direction the total distance one has to cover is the larger length. So why have we added the two?
Rajgowtham said:
1 decade ago
How the final answer comes in km per hour? First we are converting into metre per second so we need to convert it into km per hour.
Md said:
4 years ago
The answer 82 is in m/s. We want to convert it into km/hr, because in first step we convert speed into m/s by multiplying 5/18.
(5)
Sharmila said:
2 years ago
Can we convert 50 km/hr into m/s and add the speed of other trains as they are in opposite directions?
Can anyone explain me?
Can anyone explain me?
(3)
Ravi tomar said:
6 years ago
220m=0.220km : 6 sec = 1/600 hr.
0.220/ (50+x) = 1/600
0.220x600 = (50+x) => 132 = 50+x
x = 132-50=82,
x=82 km/hr.
0.220/ (50+x) = 1/600
0.220x600 = (50+x) => 132 = 50+x
x = 132-50=82,
x=82 km/hr.
Gangani said:
7 years ago
First take 220/6=36.66 m/s.
Now convert into km/h so 132km/h.
and minus 50km/h from 132 - 50 = 82km/h.
Thanks.
Now convert into km/h so 132km/h.
and minus 50km/h from 132 - 50 = 82km/h.
Thanks.
Rabvah said:
9 years ago
50*5/18 = 13.889 m/sec.
108 + 112/13.889 + x = 22.778.
Since it has to be in km/hr.
23.778*18/5 = 82 km/hr.
108 + 112/13.889 + x = 22.778.
Since it has to be in km/hr.
23.778*18/5 = 82 km/hr.
Ramesh said:
1 decade ago
(220)m
----------------- =6 sec.
((250+5x)/18)m/s
here,m and s are cancelled so x km/hr.
----------------- =6 sec.
((250+5x)/18)m/s
here,m and s are cancelled so x km/hr.
GAISINREI said:
3 years ago
First convert km/hr in m/secs,
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
x= 410/18 m/secs.
for km/hr.
41O/18 * 18/5 = 82km/hr.
Prity sahay said:
6 years ago
If everything is converted into m/s then the answer will also be 82m/s not 82 km/hr.
(1)
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