Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
48 km/hr
54 km/hr
66 km/hr
82 km/hr
Answer: Option
Explanation:

Let the speed of the second train be x km/hr.

Relative speed = (x + 50) km/hr
= [ (x + 50) x 5 ] m/sec
18
= [ 250 + 5x ] m/sec.
18

Distance covered = (108 + 112) = 220 m.

Therefore 220 = 6
( 250 + 5x (
18

=> 250 + 5x = 660

=> x = 82 km/hr.

Discussion:
77 comments Page 8 of 8.

Prathiba said:   1 decade ago
How does 660 comes in last step?

Swati hande said:   5 years ago
Thanks all for explaining.

Prem said:   6 years ago
I agree with you. @Prity.

Ankit said:   1 decade ago
Nice explanation Sanjay.

Gopal sunar said:   7 years ago
Thank you @Soumitra Das.

Nagesh said:   6 years ago
Thank you @Das.

Shubham said:   5 years ago
Thanks @Mahi.


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