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Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 25)
Problems on Trains
25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
48 km/hr
54 km/hr
66 km/hr
82 km/hr
Answer: Option
Explanation:

Let the speed of the second train be x km/hr.

Relative speed = (x + 50) km/hr
= [ (x + 50) x 5 ] m/sec
18
= [ 250 + 5x ] m/sec.
18

Distance covered = (108 + 112) = 220 m.

Therefore 220 = 6
( 250 + 5x (
18

=> 250 + 5x = 660

=> x = 82 km/hr.

Discussion:
77 comments Page 7 of 8.
Muthulakshmi said:   1 decade ago
Hai Mr.Ramesh

You are Correct.Thanks for explaining the problem clearly
Arkadev said:   6 years ago
Relative speed =220/6 * 18/5=132.
Second trains speed =132-50 = 80.
Azam Khan said:   9 years ago
How Comes 5 in answer? I can't Understand please explain this.
Amitesh said:   9 years ago
The solution is not clear for it. Can anybody solve it easily?
Priyavel said:   1 decade ago
Hi.

I can't get it clearly. Please anyone explain it.
Deepa Singh said:   1 decade ago
Please solve this part clearly 220/(5x+250)/18=6
Dharamjeet Singh said:   1 decade ago
How can the final answer come in Km/hr ??
Ashwin kumar said:   9 years ago
@Ashok.

How you get 220/250 + 5x/18?
Chanchal Tathe said:   3 years ago
@Ambika.

Good explanation. Thanks.
(3)
Purushottam said:   2 months ago
It's (220/6*18/5) - 50 = 82km/h.
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