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Aptitude - Problems on Trains

Exercise : Problems on Trains - General Questions
21.
How many seconds will a 500 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?
25
30
40
45
Answer: Option
Explanation:

Speed of the train relative to man = (63 - 3) km/hr
= 60 km/hr
= ( 60 x 5 ( m/sec
18
= ( 50 ( m/sec.
3
Therefore Time taken to pass the man
= ( 500 x 3 ( sec
50
= 30 sec.

22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
12 sec
24 sec
48 sec
60 sec
Answer: Option
Explanation:

Relative speed = = (45 + 30) km/hr
= ( 75 x 5 ( m/sec
18
= ( 125 ( m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = ( 500 x 6 ( = 24 sec.
125

23.
Two trains are running in opposite directions with the same speed. If the length of each train is 120 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:
10
18
36
72
Answer: Option
Explanation:

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)
12

=> 2x = 20

=> x = 10.

Therefore Speed of each train = 10 m/sec = ( 10 x 18 ( km/hr = 36 km/hr.
5

24.
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
10
12
15
20
Answer: Option
Explanation:

Speed of the first train = ( 120 ( m/sec = 12 m/sec.
10

Speed of the second train = ( 120 ( m/sec = 8 m/sec.
15

Relative speed = (12 + 8) = 20 m/sec.

Therefore Required time = [ (120 + 120) ] sec = 12 sec.
20

25.
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
48 km/hr
54 km/hr
66 km/hr
82 km/hr
Answer: Option
Explanation:

Let the speed of the second train be x km/hr.

Relative speed = (x + 50) km/hr
= [ (x + 50) x 5 ] m/sec
18
= [ 250 + 5x ] m/sec.
18

Distance covered = (108 + 112) = 220 m.

Therefore 220 = 6
( 250 + 5x (
18

=> 250 + 5x = 660

=> x = 82 km/hr.

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