Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
|
||||||||
|
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 7 of 9.
Dhiru said:
1 decade ago
But the pole has a length of 500m so it will take additional time to cross. Thats what I think refer example 24 both seem similar guys get clear and help me to.
Veerappan said:
1 decade ago
I accept @Durgesh, because he said well.
Faster train driver can be considered as an object like standing pole on station, slower train to pass a faster train driver is 500/75*5/18.
Faster train driver can be considered as an object like standing pole on station, slower train to pass a faster train driver is 500/75*5/18.
Durgesh said:
1 decade ago
Consider the driver as a pole is best one method to understand this Question. Answer is right.
Rahul said:
1 decade ago
Here length of both the trains moving opposite are same. The slower train first come across the driver of fast train. And then slow train cover its own distance to cross the driver. Now the slow train still has to cross the entire fast train.
That's why in this question we take distance as 500m i.e. length of slow train itself.
That's why in this question we take distance as 500m i.e. length of slow train itself.
Rohit gupta said:
1 decade ago
Its given that they are running in opposite directions and parallel to each other. And answer is given when they are running in same directions.
Dineshgct said:
1 decade ago
Here they have asked only the time taken by the slower train to pass the driver of the faster train and not the length of the entire faster train.
So here we need to consider only the length of the slower train ie.500.
So,
Time=500\(75*5/18)
Which is 24sec.
So here we need to consider only the length of the slower train ie.500.
So,
Time=500\(75*5/18)
Which is 24sec.
Manohar said:
1 decade ago
Its a simple brain teasing question.
Shro said:
1 decade ago
I agree with Pinku. If this is the way to find for slower train then what if the question is asked for faster train.
Even that will come as 24sec.
Then whats the use of asking slower and faster train in question?
OR is there any other method for it?
Even that will come as 24sec.
Then whats the use of asking slower and faster train in question?
OR is there any other method for it?
Pinku said:
1 decade ago
If it is 24sec, then time taken by faster train will be also 24.
But how is it possible that both are same. Not getting.
But how is it possible that both are same. Not getting.
Dhiru said:
1 decade ago
Both trains driver meet first then time started not before meeting
E.g
Train 1.----------> Fastest train
Train 2. <------------ Slowest train.
If they go in the way adityabala said they will never meet. So both trains driver meet when time is ZERO or they never meet.
E.g
Train 1.----------> Fastest train
Train 2. <------------ Slowest train.
If they go in the way adityabala said they will never meet. So both trains driver meet when time is ZERO or they never meet.
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