Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
12 sec
24 sec
48 sec
60 sec
Answer: Option
Explanation:

Relative speed = = (45 + 30) km/hr
= ( 75 x 5 ( m/sec
18
= ( 125 ( m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = ( 500 x 6 ( = 24 sec.
125

Discussion:
81 comments Page 1 of 9.

Chandana said:   1 decade ago
Driver is starting of the train. If slower train pass the driver of the faster train automatically it pass the total train. Is it right?

Rajesh said:   1 decade ago
Well done chandana at first I made same mistake by taking distance 1000m instead of 500.

I have got 15. Anyway, not bad.

Aarush said:   1 decade ago
This is wrong. Try formula number 8 in formula section. We shoud use distance 1000.

Sundar said:   1 decade ago
@All

Initially I was confused same like you. But, the given answer is correct.

We can assume the given question as:

A man running 45 km/hr opposite direction (against) to a train running 30 km/hr. Find the time taken by train to pass the man.

In the case of Man, Point, Pole.. the length will be considered as 0.

Note: In the given questions, IF it is mentioned like 'both train are running in SAME direction'.... then we can include the both train length (as Chandana said).

I hope this will help you a little bit. Have a nice day!

Vibhor said:   1 decade ago
Ans is correct. I did mistake at first time also.

It is a good one.

Ramakhanna said:   1 decade ago
For the complete train to cross each other, it takes 48 sec.

To cross only the initial phase i.e. engine of first train facing the end of the second train. and engine of second train facing the end of the first train,it takes the half of the time to cross the complete train i.e. 48sec/2=24 sec.

Vishwa said:   1 decade ago
Very tricky Example...

Good one...

Manasa said:   1 decade ago
Thank you sundar.

Sandeep said:   1 decade ago
Its tricky one. I made mistake in first attempt. Because I didn't read the Question well and assumed that it is asking 4 the time taken to cross each other.

Good one.

We should understand the Question well before attempting it.

Sumit said:   1 decade ago
Nothing tricky. We have to understand the concept of relative speed.

Keeping the faster train static we can consider the speed of slower train as (30+45) km/hr and as train has to pass the driver. Distance taken is 500m.

Speed=75km/hr=75*5/18m/sec.

Time taken=24sec.


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