Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
Relative speed = | = (45 + 30) km/hr | |||||||
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We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
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500 x | 6 | ![]() |
= 24 sec. |
125 |
Discussion:
81 comments Page 8 of 9.
Adityabala said:
1 decade ago
Hi, Chandana asked why don't we add the length of the train. Well this is a common doubt everybody gets .
Now you think, both are travelling in opposite direction.
Eg:
Train1 --------------> Fastest train
<---------------Train2. Slowest train
When this is the case the train1 and train2 travel with their respective speed. There will be no collision rigth because they travel in opposite direction. So we take only one length of the train that too the train we respect to .ie here we take the slower train which is 500 mts length.
Hope you got it. Have a nice day!
Now you think, both are travelling in opposite direction.
Eg:
Train1 --------------> Fastest train
<---------------Train2. Slowest train
When this is the case the train1 and train2 travel with their respective speed. There will be no collision rigth because they travel in opposite direction. So we take only one length of the train that too the train we respect to .ie here we take the slower train which is 500 mts length.
Hope you got it. Have a nice day!
(1)
Sumit said:
1 decade ago
Nothing tricky. We have to understand the concept of relative speed.
Keeping the faster train static we can consider the speed of slower train as (30+45) km/hr and as train has to pass the driver. Distance taken is 500m.
Speed=75km/hr=75*5/18m/sec.
Time taken=24sec.
Keeping the faster train static we can consider the speed of slower train as (30+45) km/hr and as train has to pass the driver. Distance taken is 500m.
Speed=75km/hr=75*5/18m/sec.
Time taken=24sec.
Sandeep said:
1 decade ago
Its tricky one. I made mistake in first attempt. Because I didn't read the Question well and assumed that it is asking 4 the time taken to cross each other.
Good one.
We should understand the Question well before attempting it.
Good one.
We should understand the Question well before attempting it.
Manasa said:
1 decade ago
Thank you sundar.
Vishwa said:
1 decade ago
Very tricky Example...
Good one...
Good one...
Ramakhanna said:
1 decade ago
For the complete train to cross each other, it takes 48 sec.
To cross only the initial phase i.e. engine of first train facing the end of the second train. and engine of second train facing the end of the first train,it takes the half of the time to cross the complete train i.e. 48sec/2=24 sec.
To cross only the initial phase i.e. engine of first train facing the end of the second train. and engine of second train facing the end of the first train,it takes the half of the time to cross the complete train i.e. 48sec/2=24 sec.
Vibhor said:
1 decade ago
Ans is correct. I did mistake at first time also.
It is a good one.
It is a good one.
Sundar said:
1 decade ago
@All
Initially I was confused same like you. But, the given answer is correct.
We can assume the given question as:
A man running 45 km/hr opposite direction (against) to a train running 30 km/hr. Find the time taken by train to pass the man.
In the case of Man, Point, Pole.. the length will be considered as 0.
Note: In the given questions, IF it is mentioned like 'both train are running in SAME direction'.... then we can include the both train length (as Chandana said).
I hope this will help you a little bit. Have a nice day!
Initially I was confused same like you. But, the given answer is correct.
We can assume the given question as:
A man running 45 km/hr opposite direction (against) to a train running 30 km/hr. Find the time taken by train to pass the man.
In the case of Man, Point, Pole.. the length will be considered as 0.
Note: In the given questions, IF it is mentioned like 'both train are running in SAME direction'.... then we can include the both train length (as Chandana said).
I hope this will help you a little bit. Have a nice day!
Aarush said:
1 decade ago
This is wrong. Try formula number 8 in formula section. We shoud use distance 1000.
Rajesh said:
1 decade ago
Well done chandana at first I made same mistake by taking distance 1000m instead of 500.
I have got 15. Anyway, not bad.
I have got 15. Anyway, not bad.
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