Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
12 sec
24 sec
48 sec
60 sec
Answer: Option
Explanation:

Relative speed = = (45 + 30) km/hr
= ( 75 x 5 ( m/sec
18
= ( 125 ( m/sec.
6

We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.

So, distance covered = Length of the slower train.

Therefore, Distance covered = 500 m.

Therefore Required time = ( 500 x 6 ( = 24 sec.
125

Discussion:
81 comments Page 6 of 9.

Baseer said:   1 decade ago
5/18 came from? Can some one tell me please.

Sandip said:   1 decade ago
The answer will be same because the length of two two trains are same. Suppose the length of two trains are different from each other, then the time taken the by each trains driver to face the each other train edge or last part, will be different.

Better you draw a picture and take the value of speed and length a little, and then solve it, and you will understand. You can take two different length of the trains or both equal length of the train. And you will get understand the problem.

Sidhant said:   1 decade ago
What If we had to find the time taken by fastest train instead of slowest train?

Nana said:   1 decade ago
Why was the speeds added instead subtracting?

Anoo said:   1 decade ago
If the question is given with specific term as driver, man in the train. We must neglect the train and only consider the driver or a man! hence you should take only train length (specified train neglecting the length of train in which man or driver is present).

ASHFAQ said:   1 decade ago
The question ask time taken to pass the driver of the faster train not the full train so we take the distance only 500.

Manorama said:   1 decade ago
Relative speed of both the trains should be consider because the faster one is also moving and it will also cover the some distance not only the slower one is moving. So since they are moving in opposite direction to each other so the relative speed will be (45+30) *5/18. And distance cover is 500+500 because both are moving so distance of both will get added. Now time taken can be calculated.

Aashu said:   1 decade ago
Why the distance is 500 ?

Msvignesh viki said:   1 decade ago
d = s/t.

(500+500) = distance = 1000.
Speed = 45kmph+30kmph = 75kmph.

Then convert it in to metre = 75*5/18 = 20.833333.
t = d/s = 1000/20.83333 = 48sec.

Then 2x(two train) = 48sec ; x = 48/2 => x = 24sec for each train.

Suryakant gupta said:   1 decade ago
See we can't add the lengths of two train because here there is no concept of crossing the train. When the driver of slower train would reach the end of faster train the both train will be symmetric. Means at the same time the driver of faster train would be at the end of slower train.

We would have added the lengths if asked about the crossing of guards in the last coaches.


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