Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
|
||||||||
|
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 4 of 9.
B Kapil said:
7 years ago
The right answer will be 24 sec because here it is talking about the time to pass the driver, so the answer will be 24 sec, not 48sec.
Kineg said:
7 years ago
Can anyone explain to me how the distance came 500?
Mubarak said:
7 years ago
@Kineg.
Distance covered = length of the slower train.
So, it is 500m.
Distance covered = length of the slower train.
So, it is 500m.
Jay said:
6 years ago
500 should be the initial distance between two trains.
Ruturaj said:
6 years ago
Not getting this, Please anyone explain it clearly.
Ankit gohel said:
6 years ago
If speed equals then what? Please tell me.
Reho Rex said:
6 years ago
This is the trick part of question no.14.
Jimmy said:
5 years ago
No @Vaidya,
24 is the right answer. Try to understand the question and then emulate the trains with two pens or pencils. You will realise that the question is asking about time taken to cover the length of only one train, not both.
24 is the right answer. Try to understand the question and then emulate the trains with two pens or pencils. You will realise that the question is asking about time taken to cover the length of only one train, not both.
Krishna said:
1 year ago
@Sahil
Speed = d/t
Speed = 125/6
t = d/speed.
t = 500/(125/6) = 500 * 6/125.
Speed = d/t
Speed = 125/6
t = d/speed.
t = 500/(125/6) = 500 * 6/125.
Dhileep said:
1 year ago
@All.
We use the length of the slower train because the problem is asking about the time it takes for the entire slower train to pass by the driver of the faster train. The calculation considers the time for the slower train to completely pass a single point (the driver), which depends on the train's full length.
We use the length of the slower train because the problem is asking about the time it takes for the entire slower train to pass by the driver of the faster train. The calculation considers the time for the slower train to completely pass a single point (the driver), which depends on the train's full length.
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