Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
|
||||||||
|
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 3 of 9.
Leaner said:
8 years ago
It should be 1000 distance because, It is clearly mention in question "500m each long".
Nitheesh said:
8 years ago
What if they had asked time for a faster train?
Can anyone solve this?
Can anyone solve this?
Pawan yadav said:
8 years ago
Yes, friends.
Because the length of train add in both condition same direction or opposite direction only speed is a minus in the same direction and add opposite direction.
Because the length of train add in both condition same direction or opposite direction only speed is a minus in the same direction and add opposite direction.
Samarya kapoor said:
9 years ago
@All.
Answer is incorrect. It should be 48 instead of 24. If the given answer is correct then look at question number 9 the same question with different value then q. 9 is incorrect.
Answer is incorrect. It should be 48 instead of 24. If the given answer is correct then look at question number 9 the same question with different value then q. 9 is incorrect.
Shyam said:
8 years ago
In the same question, Find the time taken by the faster train to pass the driver of the slower train one so whats the answer?
Neeraj said:
9 years ago
@All.
This is right because of the length of the man, pole etc is negligible, here asked only driver cross.
This is right because of the length of the man, pole etc is negligible, here asked only driver cross.
Shivank said:
9 years ago
Here we are assuming that driver is in front of the train, but generally, drivers are not in front and if the location of the driver is mentioned question will become more tricky.
Shree said:
7 years ago
Thanks for explaining the answer.
Shubham said:
7 years ago
The correct answer is 48 sec.
Paul said:
7 years ago
This sum is followed by : t= (a+b)/(u+v).
Where: a is the length of the first train.
b: length of other trains.
u and v are the respective velocity.
Where: a is the length of the first train.
b: length of other trains.
u and v are the respective velocity.
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