Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 22)
22.
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option
Explanation:
| Relative speed = | = (45 + 30) km/hr | |||||||
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We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
 Required time = |
 |
500 x | 6 |  |
= 24 sec. |
| 125 |
Discussion:
81 comments Page 9 of 9.
Msvignesh viki said:
1 decade ago
d = s/t.
(500+500) = distance = 1000.
Speed = 45kmph+30kmph = 75kmph.
Then convert it in to metre = 75*5/18 = 20.833333.
t = d/s = 1000/20.83333 = 48sec.
Then 2x(two train) = 48sec ; x = 48/2 => x = 24sec for each train.
(500+500) = distance = 1000.
Speed = 45kmph+30kmph = 75kmph.
Then convert it in to metre = 75*5/18 = 20.833333.
t = d/s = 1000/20.83333 = 48sec.
Then 2x(two train) = 48sec ; x = 48/2 => x = 24sec for each train.
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