Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 - 36) km/hr
| = |  |
10 x | 5 |  m/sec |
| 18 |
| = | |
25 | m/sec |
| 9 |
 |
2x | = | 25 |
| 36 | 9 |
2x = 100
x = 50.
Discussion:
232 comments Page 5 of 24.
Sundar said:
1 decade ago
Hi Afshu,
Since both trains are in same length, we are taking it as 2X (X + X) in order to calculate the distance.
Otherwise, if the length of the trains are different then we will take it as X1 + X2 for calculating the length.
Have a nice day!
Since both trains are in same length, we are taking it as 2X (X + X) in order to calculate the distance.
Otherwise, if the length of the trains are different then we will take it as X1 + X2 for calculating the length.
Have a nice day!
Afshu said:
1 decade ago
Thanks Sundar.
Mani said:
1 decade ago
Why we difference the speed of 2 trains ?
Jaydeep said:
1 decade ago
Why combined speed is compared to relative speed?
Jayanth said:
1 decade ago
In problem, the two trains r running on parellel lines in the same direction, how can we take both of it as same length as x . can it be two trains of different lengths running parallel. Is this is assumption or fact.
Explain me
Explain me
Prati said:
1 decade ago
I think we can do like:
Relative speed is (46-36);
Length = (10*5/18)*36;
=100both
=50 each.
Relative speed is (46-36);
Length = (10*5/18)*36;
=100both
=50 each.
Bhuvana said:
1 decade ago
How it is possible? train length = x metres then distance =2x metres.
Jelli said:
1 decade ago
It's simple
We know the formula
u=(a+b)/x-y
let us take the lengh of the train is z(both trains len are same)
then
36=(z+z)/(46-36)*5/18
z=50m
We know the formula
u=(a+b)/x-y
let us take the lengh of the train is z(both trains len are same)
then
36=(z+z)/(46-36)*5/18
z=50m
Shyam said:
1 decade ago
How can we take 2X there?
Sumi said:
1 decade ago
Hi jayanth
read the problem carefully its given that the trains of equal length
read the problem carefully its given that the trains of equal length
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