Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 7)
7.
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
50 m
72 m
80 m
82 m
Answer: Option
Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 - 36) km/hr

   = 10 x 5 m/sec
18

   = 25 m/sec
9

2x = 25
36 9

2x = 100

x = 50.

Discussion:
232 comments Page 4 of 24.

Md. Habibur Rahman said:   5 years ago
When we calculated relative speed, Why we calculate 2x?

Relative speed means a train will be static. Then we can calculate x only. Am ai right? Please tell me.
(1)

Shantanu singh parihar said:   5 years ago
We have 2x cause,
When the faster train passes to slower,
It is covering;
X+X distance(slower train +higher speed train),
So the total distance covered is 2X.
(1)

Yuva kumar said:   3 years ago
How 2x/36 = 25/9? Please explain me.
(1)

Vasanthvasu said:   2 decades ago
Length of the train =X m
by converting it into km...........

(X/36)*(18/5)=X/10 KM

X/10 = 46-36 = 10

X=100
both are same length
therefore
2X=100 ..... LENGTH OF BOTH TRAIN
X=50........ LENGTH OF EACH TRAIN

Suvarna said:   2 decades ago
But...
why this is needed???
"Let the length of each train be x metres.

Then, distance covered = 2x metres"

Akshat said:   2 decades ago
It should be mentioned that the faster train started behind the slower train.

Swapnil said:   2 decades ago
How you hav taken distance covered = 2x? please explain.

Mathan said:   2 decades ago
How you taken this as 2x? please explain.

Santhosh said:   2 decades ago
Because two trains are there.

Afshu said:   1 decade ago
Why can't we assume.

Length of the 1st train as x metres and Length of the second train as y metres?

Please explain.


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