Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
478 comments Page 5 of 48.
Apoorva Marathi said:
12 months ago
How it is 50? please explain to me.
(9)
Suja said:
3 months ago
How it 18รท5 will become? Please explain.
(9)
Raghu k said:
4 years ago
It is simple guys.
If we observe hint, her there should be the relative speed because the train and are travelling in the same direction so we (train) -v (man) T =Distance.
(120/10) (18/5) =v (t) -5.
45+5=v (t).
50=v (t).
If we observe hint, her there should be the relative speed because the train and are travelling in the same direction so we (train) -v (man) T =Distance.
(120/10) (18/5) =v (t) -5.
45+5=v (t).
50=v (t).
(8)
Priyanka devi said:
4 years ago
@Rahul.
Great work, Thanks for explaining.
Great work, Thanks for explaining.
(7)
Moses Obia said:
4 years ago
Where was 18 got from? Please explain.
(6)
Bunny said:
4 years ago
Why the speed of the train is calculated by 125 meters by 10sec?
(6)
Preetilata Das said:
3 months ago
Someone, please explain this question properly.
(6)
Sanika prakash said:
1 month ago
Good answer. Thanks all for explaining the answer.
(6)
Neha Kumari said:
1 year ago
How answer is 50 km/hr? Please explain to me.
(4)
Joy said:
2 weeks ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(4)
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