Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
478 comments Page 5 of 48.

Apoorva Marathi said:   12 months ago
How it is 50? please explain to me.
(9)

Suja said:   3 months ago
How it 18รท5 will become? Please explain.
(9)

Raghu k said:   4 years ago
It is simple guys.

If we observe hint, her there should be the relative speed because the train and are travelling in the same direction so we (train) -v (man) T =Distance.

(120/10) (18/5) =v (t) -5.
45+5=v (t).
50=v (t).
(8)

Priyanka devi said:   4 years ago
@Rahul.

Great work, Thanks for explaining.
(7)

Moses Obia said:   4 years ago
Where was 18 got from? Please explain.
(6)

Bunny said:   4 years ago
Why the speed of the train is calculated by 125 meters by 10sec?
(6)

Preetilata Das said:   3 months ago
Someone, please explain this question properly.
(6)

Sanika prakash said:   1 month ago
Good answer. Thanks all for explaining the answer.
(6)

Neha Kumari said:   1 year ago
How answer is 50 km/hr? Please explain to me.
(4)

Joy said:   2 weeks ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(4)


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