Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
493 comments Page 6 of 50.
Kiran said:
6 months ago
@Naveen reddy.
Why adding +5? please explain to me.
Why adding +5? please explain to me.
(7)
Aswitha said:
2 months ago
Why commonly mention that 5/18? please explain.
(7)
Moses Obia said:
5 years ago
Where was 18 got from? Please explain.
(6)
Bunny said:
5 years ago
Why the speed of the train is calculated by 125 meters by 10sec?
(6)
DHANASURIYA M G said:
4 weeks ago
Convert the man's speed to meters per second: 5km/hr = 5 × 10003600 ≈ 1.39m/s.
The train covers its length (125 m) in 10 seconds, so its speed relative to the man is 125m/10s = 12.5m/s.
Therefore, the speed of the train is;
12.5 m/s + 1.39 m/s ≈ 13.89 m/s.
which is converted to 50 km/hr.
The train covers its length (125 m) in 10 seconds, so its speed relative to the man is 125m/10s = 12.5m/s.
Therefore, the speed of the train is;
12.5 m/s + 1.39 m/s ≈ 13.89 m/s.
which is converted to 50 km/hr.
(6)
Ravi prasad said:
3 weeks ago
Relative speed = x - 5.
Formula:
Relative speed = Distance/time.
(x-5) 5/18 = 125/10.
X = (12. 5x18/5) + 5.
= 45 + 5 = 50km/hr.
Formula:
Relative speed = Distance/time.
(x-5) 5/18 = 125/10.
X = (12. 5x18/5) + 5.
= 45 + 5 = 50km/hr.
(5)
Jothi said:
2 decades ago
Please explain to sutract -5 but ans is 50.
(4)
Seshu said:
5 years ago
length = speed * time = 5 * 10 = 50.
(4)
Neha Kumari said:
2 years ago
How answer is 50 km/hr? Please explain to me.
(4)
Jayaprakash said:
6 months ago
How 13.89 came? Please explain to me.
(4)
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