Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
486 comments Page 1 of 49.
Supriyo Das said:
3 weeks ago
@Kiran.
There is x - 5 = 45 which means x = 45 + 5.
So, the result will be 50.
There is x - 5 = 45 which means x = 45 + 5.
So, the result will be 50.
(1)
Harshitha m said:
3 weeks ago
Can you explain in detail?
Menaka said:
4 weeks ago
Why commonly mention that 5/18? Please explain.
(6)
Kiran said:
4 weeks ago
@Naveen reddy.
Why adding +5? please explain to me.
Why adding +5? please explain to me.
(5)
Manikandan said:
1 month ago
Explain the answer.
(1)
Jayaprakash said:
2 months ago
How 13.89 came? Please explain to me.
(3)
Nether said:
2 months ago
It's 50 meters/second.
(1)
Nig said:
2 months ago
Thanks all for explaining it.
(3)
Joy said:
5 months ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(58)
Sonianenavath said:
5 months ago
Very Good Thanks.
(7)
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