Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = |  |
125 |  m/sec |
| 10 |
| = | |
25 | m/sec. |
| 2 |
| = | |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45 
x = 50 km/hr.
Discussion:
493 comments Page 2 of 50.
Kiran said:
6 months ago
@Naveen reddy.
Why adding +5? please explain to me.
Why adding +5? please explain to me.
(7)
Manikandan said:
6 months ago
Explain the answer.
(1)
Jayaprakash said:
6 months ago
How 13.89 came? Please explain to me.
(4)
Nether said:
6 months ago
It's 50 meters/second.
(1)
Nig said:
7 months ago
Thanks all for explaining it.
(3)
Joy said:
10 months ago
Here;
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
1 km = 1000m.
1 hour = 3600 seconds,
Then you change the Km/hr to m/sec.
= 1000/3600.
= 5/18 m/second.
(68)
Sonianenavath said:
10 months ago
Very Good Thanks.
(7)
Sanika prakash said:
11 months ago
Good answer. Thanks all for explaining the answer.
(14)
Aathisha Sadhasivam said:
12 months ago
How it 18÷5 will become? Please explain.
Here is the solution for this question:
The length of a train is given as 125m (here it is mentioned as m/s), and the speed is given as 5km/hr (here it is mentioned as km/hr).
While converting km/hr into m/s, we are multiplying the speed by 5/18; therefore while converting m/s into km/hr, we have to take the reciprocal of 5/18, that is 18/5. The speed of the train should be calculated in km/hr; therefore, we take 18/5.
Here is the solution for this question:
The length of a train is given as 125m (here it is mentioned as m/s), and the speed is given as 5km/hr (here it is mentioned as km/hr).
While converting km/hr into m/s, we are multiplying the speed by 5/18; therefore while converting m/s into km/hr, we have to take the reciprocal of 5/18, that is 18/5. The speed of the train should be calculated in km/hr; therefore, we take 18/5.
(32)
Suja said:
12 months ago
How it 18÷5 will become? Please explain.
(16)
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