Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
478 comments Page 3 of 48.
SoloStriver said:
1 year ago
Consider we need to convert m/sec to km/hr..
If we need to convert something from m to km, 1km=1000m. Thus 1m= (1/1000)km
So we multiply the numerator by 1/1000.
Similarly, (denominator part) for a sec to hr, 1hr=3600sec. Thus 1sec=(1/3600)hr.
So we multiply the denominator by 1/3600.
This conversion part becomes 3600/1000 thus simplifying this gives an std form of 18/5.. which is always directly used in converting m/sec conversion to km/hr.. helps in just multiplying this 18/5, instead of separate conversion of numerator and denominator to km and hr separately which is time-consuming..
Similarly, the reciprocal of this is just the vice versa case from km/hr to m/sec just multiply with 5/18.
If we need to convert something from m to km, 1km=1000m. Thus 1m= (1/1000)km
So we multiply the numerator by 1/1000.
Similarly, (denominator part) for a sec to hr, 1hr=3600sec. Thus 1sec=(1/3600)hr.
So we multiply the denominator by 1/3600.
This conversion part becomes 3600/1000 thus simplifying this gives an std form of 18/5.. which is always directly used in converting m/sec conversion to km/hr.. helps in just multiplying this 18/5, instead of separate conversion of numerator and denominator to km and hr separately which is time-consuming..
Similarly, the reciprocal of this is just the vice versa case from km/hr to m/sec just multiply with 5/18.
(26)
Ravina Sonawane said:
1 year ago
According to me, it should be 25/2 × 18/5 = 45.
(43)
Bandi Pravalika said:
1 year ago
18/5 is the direct formula to convert the m/seconds to km/hr.
In this given problem, we can convert the m/sec to km/hr so we use 18/5.
In this given problem, we can convert the m/sec to km/hr so we use 18/5.
(14)
Murugan S said:
1 year ago
HERE,
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(21)
Fizza akhtar said:
1 year ago
Suppose we have to convert km/hour into m/s.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
(11)
MAHA said:
2 years ago
How 18/5? Please explain to me.
(53)
Adesh Katiya said:
2 years ago
l = 125m,
u = 5km/hr,
v = ?
t = 10s.
u - v = 125/10 m/s,
u - v = 25/2 m/s,
u - v = 5*9 km/hr,
u - v = 45km/hr,
5km/hr - v = 45km/hr.
v = 50 km/hr.
Hence, option (B).
u = 5km/hr,
v = ?
t = 10s.
u - v = 125/10 m/s,
u - v = 25/2 m/s,
u - v = 5*9 km/hr,
u - v = 45km/hr,
5km/hr - v = 45km/hr.
v = 50 km/hr.
Hence, option (B).
(47)
Vinoda patil said:
2 years ago
To convert m/s to km/hr we use direct formula,
i.e 18/5.
Here,1km/hr = 5/18 m/sec.
To convert a given data from m/sec to km/hr we use 18/5.
i.e 18/5.
Here,1km/hr = 5/18 m/sec.
To convert a given data from m/sec to km/hr we use 18/5.
(27)
Shanthi said:
2 years ago
How this 18/5 come? please explain to me.
(17)
Sayak Chakraborty said:
2 years ago
How 18/5 came after 25/2? Please answer.
(16)
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