Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
| Speed of the train relative to man = | ![]() |
125 | m/sec |
| 10 |
| = | ![]() |
25 | m/sec. |
| 2 |
| = | ![]() |
25 | x | 18 | km/hr |
| 2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
493 comments Page 4 of 50.
PRajashree said:
2 years ago
3600sec then, 1sec = 1/3600hr.
1km =1000m then, 1m = 1/1000km.
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
1km =1000m then, 1m = 1/1000km.
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(21)
G Sekhar said:
2 years ago
This is the concept of reference of frame.
Train speed is (x)
Let's say A person in a train says that a man(outside of the train(or) beside of train running at a speed of 5 km/ hr) running slow as (x-5)km/hr.
This means if the train speed is 20 km/hr. Then the man's relative speed is as slow as 15 km/hr when compared to train speed.
This relation is mentioned in the mathematical formula as( x-5)km/hr or ( example:20-5 km/hr).
So, the relative speed is;
X - 5 = (120/10)*(18/5)
So x = 50 km/ hr.
*18/5 is used to convert m/s into km/ hr.
Train speed is (x)
Let's say A person in a train says that a man(outside of the train(or) beside of train running at a speed of 5 km/ hr) running slow as (x-5)km/hr.
This means if the train speed is 20 km/hr. Then the man's relative speed is as slow as 15 km/hr when compared to train speed.
This relation is mentioned in the mathematical formula as( x-5)km/hr or ( example:20-5 km/hr).
So, the relative speed is;
X - 5 = (120/10)*(18/5)
So x = 50 km/ hr.
*18/5 is used to convert m/s into km/ hr.
(15)
Neha Kumari said:
2 years ago
How answer is 50 km/hr? Please explain to me.
(4)
Moustafa Elhosiny said:
2 years ago
Sp of man = 5 * 5/18
= 25/18 m/sec.
Let Sp of train be x, then;
x - 25/18 = 125/10
So x = 125/10 + 25/18 = 125/9 m/sec.
So x = 125/9 * 18/5 =50 Km/h.
= 25/18 m/sec.
Let Sp of train be x, then;
x - 25/18 = 125/10
So x = 125/10 + 25/18 = 125/9 m/sec.
So x = 125/9 * 18/5 =50 Km/h.
(49)
Santhosh K said:
2 years ago
@All.
Why do we minus the speed of the man moving in the same direction? Please explain to me.
Why do we minus the speed of the man moving in the same direction? Please explain to me.
(39)
SoloStriver said:
2 years ago
Consider we need to convert m/sec to km/hr..
If we need to convert something from m to km, 1km=1000m. Thus 1m= (1/1000)km
So we multiply the numerator by 1/1000.
Similarly, (denominator part) for a sec to hr, 1hr=3600sec. Thus 1sec=(1/3600)hr.
So we multiply the denominator by 1/3600.
This conversion part becomes 3600/1000 thus simplifying this gives an std form of 18/5.. which is always directly used in converting m/sec conversion to km/hr.. helps in just multiplying this 18/5, instead of separate conversion of numerator and denominator to km and hr separately which is time-consuming..
Similarly, the reciprocal of this is just the vice versa case from km/hr to m/sec just multiply with 5/18.
If we need to convert something from m to km, 1km=1000m. Thus 1m= (1/1000)km
So we multiply the numerator by 1/1000.
Similarly, (denominator part) for a sec to hr, 1hr=3600sec. Thus 1sec=(1/3600)hr.
So we multiply the denominator by 1/3600.
This conversion part becomes 3600/1000 thus simplifying this gives an std form of 18/5.. which is always directly used in converting m/sec conversion to km/hr.. helps in just multiplying this 18/5, instead of separate conversion of numerator and denominator to km and hr separately which is time-consuming..
Similarly, the reciprocal of this is just the vice versa case from km/hr to m/sec just multiply with 5/18.
(27)
Ravina Sonawane said:
2 years ago
According to me, it should be 25/2 × 18/5 = 45.
(44)
Bandi Pravalika said:
2 years ago
18/5 is the direct formula to convert the m/seconds to km/hr.
In this given problem, we can convert the m/sec to km/hr so we use 18/5.
In this given problem, we can convert the m/sec to km/hr so we use 18/5.
(15)
Murugan S said:
2 years ago
HERE,
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(22)
Fizza akhtar said:
2 years ago
Suppose we have to convert km/hour into m/s.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
km/hour = 1000m/hour
i hour = 3600s
km/s = 1000m/3600s = 5/18.
Just reverse it, m/s into km/hour = 18/5, it's an easy way.
(12)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers

m/sec