Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
475 comments Page 7 of 48.

Saji said:   2 decades ago
18/5 is to convert m/s to km/hr
(1)

Ankita said:   2 decades ago
Why its substracted?
(1)

Gowtham said:   2 decades ago
Hey why we findind relative speed??? They asking only speed na????
(1)

Dattatray said:   1 decade ago
18/5 = 1 km/hr = 1000/3600 m/s

= 10/36 m/s

= 5/18 m/s.
(1)

Abhishek said:   1 decade ago
Distance = time * speed 125 = 10 * speed
distance/time = speed 125/10 = (25/2)m/s = speed
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Answer should be in km/hr so convert m/s
km = 1000m and hr = 3600s
m = km/1000 and s = hr/3600
m/s = (3600/1000)km/hr
m/s = (18/5)km/hr
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The condition was speed = (25/2)m/s
= (25/2)(18/5)km/hr
= 45 km/hr
The speed was relative to man so we have taken time in consideration of man
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See further in in view answer.
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(1)

Shashank shekhar said:   6 years ago
Train crossing a moving object without length in same direction:

Formula is :-
Time=length of train / ( speed of train-speed of object).
10 sec = 125 m/ ( x - 5*5/18).

So, x=125/9 m/sec = 125/9 * 18/5 km/h = 50 km/h.
(1)

Nithish raj said:   4 years ago
125/10 is for speed divide by time taken,
And 18/5 is to convert meter to kilometre
So that 125/10 is 25/2.

Multiply 25/2 by 18/5 to get in kilometre so it gets 45km/hr.
And the man running speed is 5km/hrs.
So, 45 + 5 is 50km/hrs.
(1)

Rahul said:   2 decades ago
@ vijayagopal

here both man and train are moving in the same direction and the train crosses the man in 10 seconds.

speed = distance(or length)/time.

As both man and train are moving, relative motion comes into picture.

therefore:

relative speed= (length of the train)/(time taken by the train to cross the man who is in motion)

relative speed= 125/10

Rahul said:   2 decades ago
@ankita

when a man moves in the direction of train, the train speed is decreased by his own speed. If he moves in the opposite directon he finds the train speed to be much greater. So when is moving in the same direction his speed must be subtracted from that of train speed. If he moves in the opposite direction to that of train, then his speed must be added to the train speed.

moving in same directon: SUBTRACT
moving in opposite directon: ADD

Rahul said:   2 decades ago
@gowtham
It would be only speed if the man(REFERENCE POINT) was stationary and only the train was moving. Here as both trian and REFERENCE POINT(man) are moving relative motion comes into picture.


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