Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.
x - 5 = 45
x = 50 km/hr.
Discussion:
475 comments Page 48 of 48.
Naveen said:
4 years ago
I can't understand this sum please anyone explain me briefly.
Nilesh838 said:
4 years ago
Good explanation, thanks.
Suraj kale said:
4 years ago
The object Man is also moving in the same direction as that of the train so the total distance covered should not be 125 meters.
It should be the (125+X).
Where X is the distance covered by man in 10 seconds.
It should be the (125+X).
Where X is the distance covered by man in 10 seconds.
Abinaya said:
4 years ago
Why we should reciprocal 5/18 to 18/5? Please explain.
Kushal M V said:
4 years ago
They took 18/5 because the length of train is in meter and time given which passes the man is given in seconds. To convert m/s to km/ hr they multiplied with 18/5. And the answers also in km/hr.
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