Aptitude - Problems on Trains - Discussion

Discussion Forum : Problems on Trains - General Questions (Q.No. 2)
2.
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
45 km/hr
50 km/hr
54 km/hr
55 km/hr
Answer: Option
Explanation:

Speed of the train relative to man = 125 m/sec
10

   = 25 m/sec.
2

   = 25 x 18 km/hr
2 5

   = 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr.

x - 5 = 45         x = 50 km/hr.

Discussion:
493 comments Page 4 of 50.

Murugan S said:   2 years ago
HERE,
1hr = 3600sec then, 1sec = 1/3600hr
1km =1000m then, 1m = 1/1000km
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(22)

Karthik said:   2 years ago
125/10 = 12.5,
12.5 * 3.6 = 45,
45 + 5 = 50.
(22)

PRajashree said:   2 years ago
3600sec then, 1sec = 1/3600hr.
1km =1000m then, 1m = 1/1000km.
So,
km/hr to m/s is : 1/1000km bigger divided by 1/3600hr.
So, they put 18/5.
(21)

Sheital saira said:   3 years ago
@Hemanth sairam.

Why 60 mins and 60 seconds taken there?

Please explain me.
(19)

Owona Julius said:   3 years ago
How - 5 came? Please explain this step.
(17)

Shanthi said:   2 years ago
How this 18/5 come? please explain to me.
(17)

Sayak Chakraborty said:   3 years ago
How 18/5 came after 25/2? Please answer.
(16)

Suja said:   1 year ago
How it 18รท5 will become? Please explain.
(16)

Menaka said:   5 months ago
Why commonly mention that 5/18? Please explain.
(16)

Bandi Pravalika said:   2 years ago
18/5 is the direct formula to convert the m/seconds to km/hr.

In this given problem, we can convert the m/sec to km/hr so we use 18/5.
(15)


Post your comments here:

Your comments will be displayed after verification.