Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 9)
9.
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option
Explanation:
Relative speed = (60+ 90) km/hr
| = |  |
150 x | 5 |  m/sec |
| 18 |
| = | |
125 | m/sec. |
| 3 |
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
| Required time = | |
2000 x | 3 | sec = 48 sec. |
| 125 |
Discussion:
107 comments Page 4 of 11.
Sabarish said:
1 decade ago
@Dipti
1km=1000m
1hr=60min=3600sec[one min contains 60sec then 60min having 3600sec]
here we want to convert speed(km/hr) into m/sec
so , [(1000/3600)=(5/18)]
have a nice day!
1km=1000m
1hr=60min=3600sec[one min contains 60sec then 60min having 3600sec]
here we want to convert speed(km/hr) into m/sec
so , [(1000/3600)=(5/18)]
have a nice day!
Madhav Kulkarni said:
6 years ago
Relative Speed in Opposite Direction = 60+50 = 150km/h=150*(5/18)=41.66.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
Train Length = 1.10+0.9=2Km=2000.
Time=Distance/Speed=2000/41.66=48.
So, the Answer is 48.
(2)
Shubham said:
4 years ago
@All.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
No matter about the slow or fast train, it's only a confusing statement, as no matter what speed is, both trains will cross each other at the same time.
(36)
Hsu Hsu said:
6 years ago
Why do you sum the relation speed of the train in the opposite direction?
If direction are same, will you sum?
Please, someone, explain to me, I need help!
If direction are same, will you sum?
Please, someone, explain to me, I need help!
Aasif Khan said:
1 decade ago
This is due, when we calculate time= distance/speed,
Speed is 125/3 m/sec. Therefore when we divide 2000m with 125/3 it becomes 2000 multiply by 3/125.
Speed is 125/3 m/sec. Therefore when we divide 2000m with 125/3 it becomes 2000 multiply by 3/125.
Harish Raj said:
1 decade ago
@Prateek
The time taken for faster train to cross the slower train is as equal as the time taken for slower train to cross the faster train.
The time taken for faster train to cross the slower train is as equal as the time taken for slower train to cross the faster train.
Sarang said:
7 years ago
Distance =speed*time,
1.10+.9=60+90*time,
2km=150km/h*time,
2000=150*5/18*time,
2000=750/18*time,
2000=41.66*time,
2000/41.66=time,
Time=48 s.
1.10+.9=60+90*time,
2km=150km/h*time,
2000=150*5/18*time,
2000=750/18*time,
2000=41.66*time,
2000/41.66=time,
Time=48 s.
(1)
Krishan said:
10 years ago
Why it is explicitly mentioned "time taken for faster train to cross slower train"?
I think time taken will be same for both the trains.
I think time taken will be same for both the trains.
Himanshu said:
1 decade ago
If the question be:
The time taken by the faster train to cross the slower train in seconds is. ?
What would be the working and answer?
The time taken by the faster train to cross the slower train in seconds is. ?
What would be the working and answer?
Himanshu said:
1 decade ago
Is there be any need to convert the speed and distance into mtrs? We could have been done it without converting to mtrs i.e. in kms only.
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