Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 15)
15.
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option
Explanation:
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
| = |  |
66 x | 5 |  m/sec |
| 18 |
| = | |
55 | m/sec. |
| 3 |
 Time taken to pass the man = |
|
110 x | 3 | sec = 6 sec. |
| 55 |
Discussion:
35 comments Page 3 of 4.
Buvana said:
1 decade ago
Please any one give the reason for not considering distance covered by man.
Mona said:
1 decade ago
In the question they did not mentioned that the whether the train is moving on platform are not. If they mentioned any pole are platform means we want to consider the distance of man moving in opposite direction. So I think we don't consider the distance.
Raju said:
1 decade ago
@Thili.
I agree with you.
The distance the man runs (X) towards train will be decrease the total distance, i.e 110-X mts.
Hence the time will decrease below 6 seconds.
Also since we have 2 variables distance traveled b the man towards train and the time taken for train to pass the man.
Can someone explain this solution clearly.
I agree with you.
The distance the man runs (X) towards train will be decrease the total distance, i.e 110-X mts.
Hence the time will decrease below 6 seconds.
Also since we have 2 variables distance traveled b the man towards train and the time taken for train to pass the man.
Can someone explain this solution clearly.
Shashi said:
1 decade ago
Hai friends please can you provide some formulas which are related to these problems.
Thili said:
1 decade ago
To pass the man train should go distance of train and the which was ran by the man.
Then why don't you care about the distance of man run. Train should go that distance also to pass the train.
Then why don't you care about the distance of man run. Train should go that distance also to pass the train.
Shivani said:
1 decade ago
Here is solution in simple way:.
As we know speed will add in case of opp direction so,
Speed= (60+6) =66km/h.
66*5/18=55/3m/sec (for change km/h into m/sec).
Length=110m.
Distance=s*t.
110=55/3*t.
Hence.
t=330/55=6sec.
As we know speed will add in case of opp direction so,
Speed= (60+6) =66km/h.
66*5/18=55/3m/sec (for change km/h into m/sec).
Length=110m.
Distance=s*t.
110=55/3*t.
Hence.
t=330/55=6sec.
Sarah said:
1 decade ago
@mini:
Nice explanation friend.
Nice explanation friend.
Mini said:
1 decade ago
@Arun
speed=distance/time
time=distance/speed
speed = 66*5/18 [Converting km/hr to m/sec]
= 55/3 m/sec.
Therefore, time = 110/55*3
= 110*3/55
= 6 sec
i think u will understand now
speed=distance/time
time=distance/speed
speed = 66*5/18 [Converting km/hr to m/sec]
= 55/3 m/sec.
Therefore, time = 110/55*3
= 110*3/55
= 6 sec
i think u will understand now
Arun said:
1 decade ago
hi.. can anyone just tell me why we r 55/3 as reciprocal to 3/55........? reply if u know....
Shanmu said:
1 decade ago
1 km=1000m
1 hour=3600 seconds
to convert from km/hour into m/sec
1000/3600=5/18 m/sec
got it !
1 hour=3600 seconds
to convert from km/hour into m/sec
1000/3600=5/18 m/sec
got it !
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers