Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = | ![]() |
240 | m/sec = 10 m/sec. |
| 24 |
Required time = |
![]() |
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
206 comments Page 8 of 21.
ASR said:
9 years ago
I believe the right answer is 65 Sec.
Because train speed is 10m/Sec and to cross 650-meter bridge it took 65 sec to pass that.
Because train speed is 10m/Sec and to cross 650-meter bridge it took 65 sec to pass that.
Gavendra Shah said:
9 years ago
I also think that 65 is the correct answer.
Radhakrishnan said:
10 years ago
Why can't the answer be 65 according to my explanation?
Speed of the train=(distance /time).
Hence,
240 ÷ 24 =10.
Speed of train is 10 m/s.
Time =distance /speed of the train.
For a 650m platform hence distance is 650.
Time=650m/10m/s.
Hence,
Time =65 sec.
Speed of the train=(distance /time).
Hence,
240 ÷ 24 =10.
Speed of train is 10 m/s.
Time =distance /speed of the train.
For a 650m platform hence distance is 650.
Time=650m/10m/s.
Hence,
Time =65 sec.
Balaji.P said:
10 years ago
I think we don't need to add both the meters of the platform.
Binjith said:
10 years ago
Speed = total (distance/time).
240/24sec = 10 ms.
So, 650/10ms = 65 sec.
240/24sec = 10 ms.
So, 650/10ms = 65 sec.
SmitaBhutka23 said:
10 years ago
I have a simple solution.
Speed = distance/time;
240/24 = 10 m/s is speed of train.
Now pltform length is 650 m.
We have speed of train nd platform length.
so, time for crossing platform=length of platform/speed of train(t=d/s),
T(time for crossing platform)=650/10 = 65.
Here 65 is the time taken by the part of engine to cross the platform, not by the entire train.
24 second is time taken by train to reach to the pole + 65 sec is time tacken by train to cross the platform = 89 sec.
Speed = distance/time;
240/24 = 10 m/s is speed of train.
Now pltform length is 650 m.
We have speed of train nd platform length.
so, time for crossing platform=length of platform/speed of train(t=d/s),
T(time for crossing platform)=650/10 = 65.
Here 65 is the time taken by the part of engine to cross the platform, not by the entire train.
24 second is time taken by train to reach to the pole + 65 sec is time tacken by train to cross the platform = 89 sec.
Faisal said:
10 years ago
The solution is correct.
If we don't add 240 we will get only the time taken for the engine to travel and not the entire train.
So we have to add it.
If we don't add 240 we will get only the time taken for the engine to travel and not the entire train.
So we have to add it.
Akshay said:
10 years ago
Please let me know about the solution.
I'm not getting this. someone help me.
I'm not getting this. someone help me.
Santosh devre said:
10 years ago
65 answer is correct.
I too get the answer as 65.
I too get the answer as 65.
Nandhu said:
10 years ago
Pole:
Speed = lengh/time.
= 240/24,
= 10m/s.
Platform:
Time = length/speed.
= (240 + 650)/10,
= 89s.
Speed = lengh/time.
= 240/24,
= 10m/s.
Platform:
Time = length/speed.
= (240 + 650)/10,
= 89s.
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m/sec = 10 m/sec.
Required time =