Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = | ![]() |
240 | m/sec = 10 m/sec. |
| 24 |
Required time = |
![]() |
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
206 comments Page 7 of 21.
Roy7829 said:
9 years ago
Length of train(distance)=240m
Time=24sec
Formula: length(distance)=speed x time
240=speed x 24
speed=240/24
speed=10sec.
Now it has to pass platform of 650m
The total length of platform =650m
train length = 240m
The total distance the train pass the platform = 650+240=890m.
Because as the train entered the platform(650m) the train remaining part was outside the platform (240m).
So total distance the train cover is 890.
Time=24sec
Formula: length(distance)=speed x time
240=speed x 24
speed=240/24
speed=10sec.
Now it has to pass platform of 650m
The total length of platform =650m
train length = 240m
The total distance the train pass the platform = 650+240=890m.
Because as the train entered the platform(650m) the train remaining part was outside the platform (240m).
So total distance the train cover is 890.
Karthikeyan said:
9 years ago
Why we are adding the time of poles with the time of platforms?
Rajiv sd said:
9 years ago
Here pole consider as a point of reference, but platform not a point if consider engine only cross the platform from starting of platform to end (i.e also consider as crossed) 65 sec is correct, but if consider entire train (engine to the last van) cross the platform end to end length of the platform should be added hence 89sec is correct.
Akhil bhatt said:
9 years ago
89 sec is the correct answer.
Sai said:
9 years ago
Since the train has to cross the platform, it is not on the platform. It has to completely cross the platform means it crosses it's length.
Therefore total distance becomes train's length+ platform's length =890m.
Time = 890/10 = 89sec.
Therefore total distance becomes train's length+ platform's length =890m.
Time = 890/10 = 89sec.
SREERAM said:
9 years ago
Pole is given to just calculate the speed of the train, In the question, nowhere mention pole is on the platform so the answer is 65 m/s.
Saketh said:
9 years ago
Yes, you are right @Kumar.
Mir Rokon uddin. said:
9 years ago
To me, answer is 41 if the pole and the platform consider separately.
650-240=410.
Now it crosses 240m in 24s.
So, 410m in 41s.
If both pole and platform consider jointly the answer will be 89s. I understood 2nd case. But my Mind also with the 1st case. I think the question is ambiguous. Or am I wrong?
650-240=410.
Now it crosses 240m in 24s.
So, 410m in 41s.
If both pole and platform consider jointly the answer will be 89s. I understood 2nd case. But my Mind also with the 1st case. I think the question is ambiguous. Or am I wrong?
Aravind said:
9 years ago
I Can't understand. Please explain me.
ABHISHEK BALIYAN said:
9 years ago
The answer has to be 89 seconds if it is given that this pole is a point of reference on the platform or bridge but is is not mentioned that pole is on the platform thus both the answers are correct it's a tricky question because of the language of the question (consider the question where we give conditions such as a man is standing on a platform that would help you to understand the concept better).
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m/sec = 10 m/sec.
Required time =