Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 13 of 21.
Rajesh lodhi said:
1 decade ago
Please solve this question.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
Bunny said:
1 decade ago
By adding 240+650, it says the distance travelled by the whole train to cross the platform.
Nagesh Shirsat said:
1 decade ago
Well the question is how long train take to cross the platform, in order to do so, train has to cover total length of platform i.e. 650 m and its own length i.e. 240 m, hence 240+650/10=89. 65 is when the engine crosses the platform, it has got to travel train length too to cross the platform entirely. I hope all doubts are clear now.
Mallikarjun said:
1 decade ago
24 ........> 240.
? ........> 240+650 = 890.
89 sec.
? ........> 240+650 = 890.
89 sec.
Chandu said:
1 decade ago
I got a doubt!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
Pon said:
1 decade ago
Let length of the train = l = 240m.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
Vatsal Patel said:
1 decade ago
I think many people are confusing why we add train length here. The train crosses the bridge means that initially its engine was at starting of the bridge and when it has crossed the bridge, the last bogy of the train is on the other end of the bridge. And engine will be quite ahead by the length of train. So actually the train travels the distance 240+650 in this case when we consider only its engine for ease.
Leela venkateswara aro said:
1 decade ago
Let length of the train=l=240m.
Time taken to cross platform=t=?
Platform length=a=650m.
Speed of the train=S= (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s =240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
During this time the train has to cross its own length as well as platform length.
Time taken to cross platform=t=?
Platform length=a=650m.
Speed of the train=S= (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s =240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
During this time the train has to cross its own length as well as platform length.
Kishor said:
1 decade ago
For speed of the train (assume Z).
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
[distance = speed x time].
240 = Z x 24.
Z = 240/24.
Z = 10m/sec.
Let assume time is Y,
Length of the platform = (speed x time) - length of train.
650 = (10xY)-240.
Y = (650+240)/10.
Y = 89sec.
Jitendra barod said:
1 decade ago
Speed = 240/24 = 10.
Speed = total distance/time.
Time = total distance/speed = (240+650)/10 = 89 sec.
Speed = total distance/time.
Time = total distance/speed = (240+650)/10 = 89 sec.
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