Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = | ![]() |
240 | m/sec = 10 m/sec. |
| 24 |
Required time = |
![]() |
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
206 comments Page 13 of 21.
Manoj said:
1 decade ago
Time taken by a train of length l meters to pass a stationery object of length b meters is the time taken by the train to cover (l + b) meters.
So its (650+240)/100.
So its (650+240)/100.
Basavaraj S G said:
1 decade ago
Hello guys.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
K.anusha said:
1 decade ago
Please explain 240+650/10?
Divyan said:
1 decade ago
Why we can't minus 240 and 650. Please. Help me to know when should we add and when should we minus?
What is the meaning of engine crossing in 65?
What is the meaning of engine crossing in 65?
Rajesh lodhi said:
1 decade ago
Please solve this question.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
A passenger train, 150m long.
Passage a railway platform 200 m long in 34 sec time taken by this train to pass a stationary man is.
Please help me anyone me to solve this question systematically.
Bunny said:
1 decade ago
By adding 240+650, it says the distance travelled by the whole train to cross the platform.
Nagesh Shirsat said:
1 decade ago
Well the question is how long train take to cross the platform, in order to do so, train has to cover total length of platform i.e. 650 m and its own length i.e. 240 m, hence 240+650/10=89. 65 is when the engine crosses the platform, it has got to travel train length too to cross the platform entirely. I hope all doubts are clear now.
Mallikarjun said:
1 decade ago
24 ........> 240.
? ........> 240+650 = 890.
89 sec.
? ........> 240+650 = 890.
89 sec.
Chandu said:
1 decade ago
I got a doubt!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
Train length = 240m.
Here in this case platform is independent of train length it is just the speed!
So I feel 65 sec is the answer.
Any suggestions please!
Pon said:
1 decade ago
Let length of the train = l = 240m.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
Time taken to cross platform = t = ?
Platform length = a = 650m.
Speed of the train = S = (length of the train+length of platform)/time taken to cross platform.
s = (240+650) /t.
s = 240/24=10m/s.
10 = 890/t.
T = 890/10 = 89sec.
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m/sec = 10 m/sec.
Required time =