Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 6)
6.
A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option
Explanation:
| Speed = |  |
240 |  m/sec = 10 m/sec. |
| 24 |
 Required time = |
|
240 + 650 | sec = 89 sec. |
| 10 |
Discussion:
202 comments Page 12 of 21.
Givid said:
1 decade ago
240+650/10.
Why do we divide it by 10 sec finally?
Why do we divide it by 10 sec finally?
Raja said:
1 decade ago
The time taken by the train to cross the pole so the train passing the pole (time) is 24sec.
240m = 24secs.
650m = 65secs.
The time taken by the train to passing the station is 65+24 = 89sec.
240m = 24secs.
650m = 65secs.
The time taken by the train to passing the station is 65+24 = 89sec.
Riya said:
1 decade ago
Yes it takes 65 secs for the front part of the train to reach the platform end but what we need to find is the time taken by the complete train to pass the platform.
i.e. we need to add the time taken to travel a distance equal to its own length.
i.e 65+(240/10) = 89 seconds. 65 seconds is definitely not the answer.
i.e. we need to add the time taken to travel a distance equal to its own length.
i.e 65+(240/10) = 89 seconds. 65 seconds is definitely not the answer.
Vicky said:
1 decade ago
I'm thinking that if it takes 24 seconds to cross 240 m.
Then it takes 48 sec s to cross 480 m with constant speed.
So it takes 240 m = 24 sec.
10 m = 1 sec.
To pass 650 m it takes 65 secs. I'm sure whether this is correct or not. I'm sure that question is not clear.
Then it takes 48 sec s to cross 480 m with constant speed.
So it takes 240 m = 24 sec.
10 m = 1 sec.
To pass 650 m it takes 65 secs. I'm sure whether this is correct or not. I'm sure that question is not clear.
Sudarsan said:
1 decade ago
Given train distance is = 240 m.
Platform distance = 650 m.
Speed of train = 240/24= 10 m/s.
Let the platform be AB = 650 m.
And train length be CD = 240 m.
The time taken is 65 s for D of the train (the front part).
Thus for the train to completely pass i.e. C to pass the total distance is (240 + 650 m).
Thus time taken for the train to pass is 89 s.
Platform distance = 650 m.
Speed of train = 240/24= 10 m/s.
Let the platform be AB = 650 m.
And train length be CD = 240 m.
The time taken is 65 s for D of the train (the front part).
Thus for the train to completely pass i.e. C to pass the total distance is (240 + 650 m).
Thus time taken for the train to pass is 89 s.
Arun said:
1 decade ago
I think that if they asked how long it will take to cross the pole and platform means 89 is correct but platform alone means 65 because speed of the trains 10m/s.
Manoj said:
1 decade ago
Time taken by a train of length l meters to pass a stationery object of length b meters is the time taken by the train to cover (l + b) meters.
So its (650+240)/100.
So its (650+240)/100.
Basavaraj S G said:
1 decade ago
Hello guys.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
W.k.t, speed = dist/time.
So on comparing,
Dist/time = dist/time.
240/24 = (240+650)/t.
t = (890/24)/240.
t = 89 sec.
K.anusha said:
1 decade ago
Please explain 240+650/10?
Divyan said:
1 decade ago
Why we can't minus 240 and 650. Please. Help me to know when should we add and when should we minus?
What is the meaning of engine crossing in 65?
What is the meaning of engine crossing in 65?
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