Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 34 of 61.
VVVR said:
1 year ago
1km = 1000m.
1hour = 3600sec.
1000/3600 = 5/18 mps.
1hour = 3600sec.
1000/3600 = 5/18 mps.
(87)
Pallavi Ananda Morbale said:
11 months ago
Very Good, Thanks everyone for explaining the answer.
(2)
Najrul Shaikh said:
1 decade ago
Save = (1-0.55-0.15)x = 12,750.
Salary = x = 42,500.
Salary = x = 42,500.
Sandeep said:
9 years ago
@Kalimuthu.
Thank you, I can easily understand now.
Thank you, I can easily understand now.
RAKESH KUMAR said:
9 years ago
Very good explanations, Thank you very much for all.
SSHA said:
1 month ago
Why should I take 5/18, can you please explain that?
(4)
Latha said:
1 decade ago
Hi Vishnu.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
Geetha(VG) said:
1 decade ago
Can you explain the encoding and decoding problems?
Swarit said:
3 years ago
60*5/18 = 50/3.
50/3 *9,
Then 50*3.
Answer = 150.
50/3 *9,
Then 50*3.
Answer = 150.
(7)
Lokesh said:
3 years ago
Why do we use 5/18. Can anybody explain me? please.
(51)
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m/sec
Length of the train =