Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 33 of 61.
Pooja said:
1 decade ago
Hi.Thank you for guiding students for MCA & MBA...
Reddy said:
1 decade ago
@Rita
Please explain this problem I am not understand.
Please explain this problem I am not understand.
Sam prakash shine said:
9 years ago
@Suraj.
5/18 is for converting the km/hour into m/sec.
5/18 is for converting the km/hour into m/sec.
Sarang said:
8 years ago
Distance = speed*time.
60*5/18*9,
60*5/2,
300/2 = 150.
60*5/18*9,
60*5/2,
300/2 = 150.
Gowrishankar said:
1 year ago
For km;
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
(2)
Mark said:
1 decade ago
Length of the train = (Speed x Time) = 50x9 m = 150 m.
Pallavi said:
6 years ago
Explanations are very clear to understand. Thanks all.
Alavaala Praveen Kumar said:
3 years ago
60 * 5/18 = 50/3.
50/3 * 9,
Then 50 * 3,
Answer = 150.
50/3 * 9,
Then 50 * 3,
Answer = 150.
(15)
Poonam said:
1 decade ago
No need of MBA & MCA coaching classes. Thank you.
Raj said:
1 decade ago
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
50/3*9 = 150mtrs.
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