Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 33 of 59.
Poonam said:
1 decade ago
No need of MBA & MCA coaching classes. Thank you.
Raj said:
1 decade ago
Speed = [60*5/18]m/sec=50/3 m/sec.
50/3*9 = 150mtrs.
50/3*9 = 150mtrs.
VVVR said:
12 months ago
1km = 1000m.
1hour = 3600sec.
1000/3600 = 5/18 mps.
1hour = 3600sec.
1000/3600 = 5/18 mps.
(87)
Pallavi Ananda Morbale said:
7 months ago
Very Good, Thanks everyone for explaining the answer.
(2)
Najrul Shaikh said:
1 decade ago
Save = (1-0.55-0.15)x = 12,750.
Salary = x = 42,500.
Salary = x = 42,500.
Sandeep said:
9 years ago
@Kalimuthu.
Thank you, I can easily understand now.
Thank you, I can easily understand now.
RAKESH KUMAR said:
8 years ago
Very good explanations, Thank you very much for all.
Latha said:
1 decade ago
Hi Vishnu.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
Geetha(VG) said:
1 decade ago
Can you explain the encoding and decoding problems?
Swarit said:
3 years ago
60*5/18 = 50/3.
50/3 *9,
Then 50*3.
Answer = 150.
50/3 *9,
Then 50*3.
Answer = 150.
(7)
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