Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 32 of 59.
Renu patel said:
9 years ago
Really great explanation of the solution. Thank you all.
SRIRAM said:
6 months ago
Why we are calculating 5/18 not 18/5? Please explain it.
(23)
Pooja said:
1 decade ago
Hi.Thank you for guiding students for MCA & MBA...
Reddy said:
1 decade ago
@Rita
Please explain this problem I am not understand.
Please explain this problem I am not understand.
Sam prakash shine said:
9 years ago
@Suraj.
5/18 is for converting the km/hour into m/sec.
5/18 is for converting the km/hour into m/sec.
Sarang said:
7 years ago
Distance = speed*time.
60*5/18*9,
60*5/2,
300/2 = 150.
60*5/18*9,
60*5/2,
300/2 = 150.
Gowrishankar said:
8 months ago
For km;
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
a/hr = (a*5%18).
And for m;
a/hr = (a * 18%5).
(2)
Mark said:
1 decade ago
Length of the train = (Speed x Time) = 50x9 m = 150 m.
Pallavi said:
6 years ago
Explanations are very clear to understand. Thanks all.
Alavaala Praveen Kumar said:
3 years ago
60 * 5/18 = 50/3.
50/3 * 9,
Then 50 * 3,
Answer = 150.
50/3 * 9,
Then 50 * 3,
Answer = 150.
(15)
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