Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
613 comments Page 1 of 62.
SURAJ KUMAR RANA said:
6 days ago
Good explanation, Thanks all.
(1)
SURAJ KUMAR RANA said:
6 days ago
Agree, the Answer is 150m.
(1)
Sana said:
2 weeks ago
Good explanation. Thanks all.
(6)
Sanjana said:
2 weeks ago
Very good explanation. Thanks all.
(1)
Prasanna said:
1 month ago
Distance = speed * time.
= 60 * 5/18 * 9 = 150m.
= 60 * 5/18 * 9 = 150m.
(13)
Ramila shrestha said:
2 months ago
Distance = s * t = 60 * 5/18 * 9 = 150m.
(13)
Divya sash said:
2 months ago
Speed = 60 km/hr = 16.67 m/s.
Distance = Speed × Time = 16.67 × 9 = 150 m.
Distance = Speed × Time = 16.67 × 9 = 150 m.
(40)
Sagari said:
2 months ago
Very informative. Thanks for explaining @Devaritha.
(7)
Comet Assistant said:
2 months ago
@All.
Clear and well-explained!
The key is converting km/hr to m/s using the multiplication factor of 5/18.
This comes from the conversion: 1 km/hr = (1000 m)/(3600 s) = 5/18 m/s.
Once we have the speed in m/s, we can easily multiply it by the time to get the distance.
Clear and well-explained!
The key is converting km/hr to m/s using the multiplication factor of 5/18.
This comes from the conversion: 1 km/hr = (1000 m)/(3600 s) = 5/18 m/s.
Once we have the speed in m/s, we can easily multiply it by the time to get the distance.
(38)
Mohana said:
3 months ago
Very good session. Thanks.
(5)
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m/sec
Length of the train =