Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
Discussion:
587 comments Page 31 of 59.
Parth said:
9 years ago
60min -> 60km.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
Devkar Sunil said:
8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.
9sec=?.
Cross multipication =150m.
Sudharsan said:
1 decade ago
Let the length of the train be x.
3600/9=6000/x.
X=150m !
3600/9=6000/x.
X=150m !
SunnYnikkS said:
9 years ago
Ya, now all the people can solve these type of questions.
Test said:
9 years ago
ta, now all the people can solve these type of questions.
Ayushi said:
9 years ago
@All.
Very good explanation thanks a lot for helping us.
Very good explanation thanks a lot for helping us.
Saipriya said:
8 months ago
1km = 1000m,
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
1hr = 3600s.
1km/hr = 1000/3600.
= 5/18 m/s.
(38)
Raja said:
1 decade ago
What is the shortcut method to calculate gcf of numbers?
Sanket said:
1 decade ago
Give me Different type of Examples on same logical base.
Manjesh said:
9 years ago
60 * 5/18 = 16.6666667. Then, Why it is divided by 50/3?
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