Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
609 comments Page 31 of 61.
Mohammad jabir said:
2 months ago
Please explain this problem because I can't understand this.
(6)
Vishnu said:
1 decade ago
(sqrt(3N))^3/2 = 90
How to find N value from this problem?
How to find N value from this problem?
Thiru said:
6 years ago
36sec ---> 600m.
9sec ------> 600 * 9/36 = 150meters.
9sec ------> 600 * 9/36 = 150meters.
Arun said:
2 years ago
1km = 1000 meters.
1 hour = 3600 sec.
So, 1000/3600 = 5/18.
1 hour = 3600 sec.
So, 1000/3600 = 5/18.
(13)
Yash Singh said:
2 years ago
Length= Speed * Time.
Length = 60*(5/18)*9,
Length = 150m.
Length = 60*(5/18)*9,
Length = 150m.
(27)
Edward Casandra oghenekaro said:
2 years ago
Here, how did you get the 50? Anyone, please explain to me.
(42)
Arunkumar said:
1 decade ago
It's simple but don't use our brain in finding the answer.
Sri said:
1 decade ago
If the answer means options are in KM what is the process?
Parth said:
9 years ago
60min -> 60km.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
1min ->1km.
10sec ->166.
So, 9sec -> 149.5.
Devkar Sunil said:
8 years ago
1hr(3600sec)=60 * 1000.
9sec=?.
Cross multipication =150m.
9sec=?.
Cross multipication =150m.
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m/sec
Length of the train =