Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
626 comments Page 35 of 63.
SSHA said:
6 months ago
Why should I take 5/18, can you please explain that?
(5)
Latha said:
1 decade ago
Hi Vishnu.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
(sqrt(3N))^3/2 = 90.
N=?
Answer: N=10.
Geetha(VG) said:
1 decade ago
Can you explain the encoding and decoding problems?
Swarit said:
4 years ago
60*5/18 = 50/3.
50/3 *9,
Then 50*3.
Answer = 150.
50/3 *9,
Then 50*3.
Answer = 150.
(7)
Lokesh said:
3 years ago
Why do we use 5/18. Can anybody explain me? please.
(51)
Sarita said:
3 years ago
Why do we use 5/18? Can anybody explain me? please.
(44)
Anil Magar said:
2 years ago
@Anuradha.
= 50/3*9.
= 16.6666667*9,
= 150M answer.
= 50/3*9.
= 16.6666667*9,
= 150M answer.
(9)
Mohan said:
2 years ago
@All.
Here, Speed of the train = 60×(5/18) = 50/3.
Here, Speed of the train = 60×(5/18) = 50/3.
(2)
Sagari said:
5 months ago
Very informative. Thanks for explaining @Devaritha.
(8)
MOTHI said:
1 decade ago
Its simple but we should remember how 5/18 exists?
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m/sec
Length of the train =