Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = | ![]() |
60 x | 5 | m/sec |
= | ![]() |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
Length of the train = |
![]() |
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
597 comments Page 24 of 60.
Irine said:
8 years ago
I have one doubt.
Why don't you change 9sec into hours and then calculate distance?
Why don't you change 9sec into hours and then calculate distance?
Elamathi.A said:
1 decade ago
A bus crossing a 42 kilometers in 50 minutes. What is the average speed of the bus?
Vikas Prasad said:
9 years ago
I am not able to solve the problem. Please help me by explaining the simple method.
Iram said:
1 decade ago
How its possible L = 60*5/18*9 = 60-5/2?
In this 2 is where from come give reply?
In this 2 is where from come give reply?
Naveen said:
2 years ago
60 * 60 = 3600,
1000/3600 = 5/18,
60Km/hr.
1km = 1000m,
1hr = 60min.
1sec = 60sec.
1000/3600 = 5/18,
60Km/hr.
1km = 1000m,
1hr = 60min.
1sec = 60sec.
(14)
Padma said:
9 years ago
I cannot understand this problem (6 * (5/18) * 9) = 150. Pease explains briefly.
Dinesh said:
1 decade ago
It has come approximately 150.03 is this correct or exact answer should be 150.
Without formula said:
8 years ago
@Aditya.
15%+55% = 70,
30%?
12750÷ 30 = 425*70 = 29750 + 12750 = 42500ans.
15%+55% = 70,
30%?
12750÷ 30 = 425*70 = 29750 + 12750 = 42500ans.
Janeth said:
1 decade ago
@Jayath how about -14x/100. I do not understand. Where did you get the number?
Murali said:
3 years ago
Length = time/speed.
= 9sec/60kmhr.
= 0.15km = 150meter.
= 9sec/60kmhr.
= 0.15km = 150meter.
(49)
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m/sec
Length of the train =