Aptitude - Problems on Trains - Discussion
Discussion Forum : Problems on Trains - General Questions (Q.No. 1)
1.
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option
Explanation:
| Speed = |  |
60 x | 5 |  m/sec |
= | |
50 | m/sec. |
| 18 | 3 |
Length of the train = (Speed x Time).
 Length of the train = |
|
50 | x 9 | m = 150 m. |
| 3 |
Discussion:
587 comments Page 25 of 59.
Raji said:
1 decade ago
I couldn't expect that for a single question which is having so many methods.
MM Aishwarya said:
8 months ago
Length = speed × time.
60*(5/18) = 50/3
(50/3)*9 = 150.
Length = 150 metres.
60*(5/18) = 50/3
(50/3)*9 = 150.
Length = 150 metres.
(6)
Meenakshi said:
10 years ago
Thanks for all of you for the kind explanation it's very easy to understand.
ANNAMALAI said:
10 years ago
1 km = 1000 m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
60 km = 60000 m.
1 hr = 3600 sec.
= (60000/3600)*9 = 150m.
Rajakumara said:
3 years ago
It's a very good explanation to understand the equation. Thanks, everyone.
(5)
Shyam Prasanth said:
2 years ago
= 60×5/18.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
= 300/18 (50×6=300 ,3×6=18).
= 50/3,
= 50/3×9,
= 50×3,
= 150.
(12)
Grace said:
1 decade ago
60000 = 3600.
x = 9.
Cross multiply.
= 3600 x/60000*9.
Answer is 150.
x = 9.
Cross multiply.
= 3600 x/60000*9.
Answer is 150.
Shoaib soudagar said:
8 years ago
You can simply solve like this.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
1 0mtrs/1hr * second.
1000/60 * 9 = 150.
Arun s said:
2 years ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(94)
Ritik negi said:
11 months ago
1 km = 1000 m,
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
1 hr has 3600 sec.
So, 1 km/hr = 1000m/3600s = 5/18 m/s.
(106)
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