Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 6 of 8.
Amrith said:
1 decade ago
Three times the first of three consecutive odd integers.
Why is 3x taken didn't get it.
Why is 3x taken didn't get it.
Muthu said:
1 decade ago
Hi guys. Any one clear my doubt.
3x = 2(x+4)+3.
How can you get above steps ?
3x = 2(x+4)+3.
How can you get above steps ?
Shanu kumar said:
6 years ago
Odd numbers are never be in form of x, x+2 etc.
Odd no Is in the form of 2x+1.
Odd no Is in the form of 2x+1.
(3)
Raj said:
1 decade ago
Any one can explain these problems why we assume the number as X+1, X+2X, X+3?
Aryan said:
4 years ago
Here
Three odd consecutive number.
3, 5, 7 = 3 + 5 + 7 then ans 15.
Three odd consecutive number.
3, 5, 7 = 3 + 5 + 7 then ans 15.
(32)
Ramya said:
7 years ago
Anyone can explain this problem? Please anyone help me to solve this problem.
(2)
Kamal said:
1 decade ago
How can we take x, x+2, x+4 as odd positive integers. Kindly clear my doubt?
Srinu said:
1 decade ago
I don't understand this problem. Can any one explain this problm please.
Prabhu said:
1 decade ago
How will come? please explain. I couldn't understand.
3x = 2(x+4)+3.
3x = 2(x+4)+3.
Virendra said:
1 decade ago
Forget everything just go option wise then answer should be 9 or 15.
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