Aptitude - Problems on Numbers - Discussion

Here

Three odd consecutive number.
3, 5, 7 = 3 + 5 + 7 then ans 15.

Let three consecutive odd integers are: x, x+2,x+4.

Three times the first of three integers, so--> 3x; is 3 more than twice the third so--> 3+ 2(x+4).

Then, we get an equation like 3x=3+2(x+4).
=3+2x+8.
3x-2x=11
X=11.

So, the third integer is x+4=15.

The first three odd numbers,

X, X+2, X+4.

in the question they've mentioned 3 times the 1st odd number(which is X)

So, 3X.
Then they've mentioned 3 more than twice of the third number 3+2(X+4).
then;

3x = 3+ 2(x + 4).
3x = 3+ 2x + 8.
3x - 2x = 3 + 8.
x = 11.

So, the ans is 11 +4 => 15.

Here,
1,3,5 three odd consecutive no;
Three times the first of three consecutive odd integers is 3 more than twice the third,
3x when the third inter is x=5.
3*5=15.

Suppose we take x,x+2,x+4 for odd consecutive numbers;

Then, according to the question, the first among the consecutive number is 3 more than twice the third number.

It means 3x+3=2(x+4) then;
we will get 3x+3=2x+8(now collecting like terms);
then 3x-2x=8-3.

x=5
So the third number is x+4----->>>> 9.

The Consecutive odd integers are (2x+1, 2x+3, 2x+5). Sub any no.for 'x', you'll get an odd integer.

Now, try solving the question with these three, you'll get X = 5;
That means the 3rd integer, 2X + 5 = 15.

Odd numbers are never be in form of x, x+2 etc.
Odd no Is in the form of 2x+1.

My answer is 15.

Let 2n+1 be an odd number for any value of n from 0 up to infinity.

Take a look: If n=0, 2n+1 is 1. If n=1, 2n+1 is 3. See, the resulting number is always odd whether n is odd or even.

Let (2n+1), (2n+3), (2n+5) be the three consecutive numbers.
Just to see if these three are really consecutive odd, let us try to substitute n=0. If n=0, the resulting three consecutive odd are 1,2,3. If n=1, the resulting three consecutive odd are 3,5,7. This is just to show you that these three will really result to three consecutive odd for any value of n from 0 up to infinity.

Since we do not know exactly what are these three consecutive odd, so let us take these (2n+1), (2n+3), (2n+5) as the three consecutive odd numbers.

Solution:
3(2n+1) = 2(2n+5)+3
6n+3 = 4n+10+3
6n-4n = 10+3-3
2n = 10
n = 5.
Since the third odd number is represented by 2n+5, just substitute 5 to n. So the third odd number is 15.

We can also say that the three consecutive odds are 11, 13, 15. The third is 15.

Anyone can explain this problem? Please anyone help me to solve this problem.

X+1, X+3, X+5.
Atq:
3(X+1) = 3+2(X+5),
X = 10.