# Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
9
11
13
15
Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3      x = 11.

Third integer = x + 4 = 15.

Video Explanation: https://youtu.be/_77C9YE321Y

Discussion:
75 comments Page 1 of 8.

Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.

0 is considerd as even number.

Sandeep pote said:   1 decade ago
Third integer would be 9.

Explanation:

Suppose 3 numbers are . . x, x+2, x+4.

3x = 2(x + 4) - 3

3x = 2x + 8 -3

x = 5

Then third number is 5 + 4 = 9.

Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be

3x+3=2(x+4),therefore x=5

So, the third no. is x+4=5+4=9.

Here 3 more than that of the value of x so we use.

3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.

The first part is 3 more than the second part.

So to equate it we have to add 3 to the second part

I part = II part + 3

The ans 15 is correct

Md. Saifur Rahman said:   1 decade ago
2x+1, 2x+3, 2x+5
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15

Rahman is right.

Because the given numbers should be odd numbers.

So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5

In this problem, they had given three consecutive odd integers.

If we take that 3 odd integers as x , x+2 and x+4,

if we put x = 2 => the numbers will become 2 , 4, 6

these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers?

Can anyone Clear my doubt??

Vamshidhar reddy said:   1 decade ago
Three consecutive integers x, x+1, x+2

3x=2(x+2)+3
x=7
x+2=9