Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 1 of 8.
Saji said:
1 decade ago
Hai can any one clear my doubt. They have mentioned it as three consecutive odd integers. If 0 is substituted in the place of x it becomes three even integers.
Nilesh said:
1 decade ago
0 is considerd as even number.
Sandeep pote said:
1 decade ago
Third integer would be 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Explanation:
Suppose 3 numbers are . . x, x+2, x+4.
3x = 2(x + 4) - 3
3x = 2x + 8 -3
x = 5
Then third number is 5 + 4 = 9.
Bharghavi said:
1 decade ago
The answer would be 9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Explanation:
Suppose 3 nos. are x,x+2,x+4
The equations would be
3x+3=2(x+4),therefore x=5
So, the third no. is x+4=5+4=9.
Nishanthi said:
1 decade ago
Here 3 more than that of the value of x so we use.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.
FRANCO said:
1 decade ago
The first part is 3 more than the second part.
So to equate it we have to add 3 to the second part
I part = II part + 3
The ans 15 is correct
So to equate it we have to add 3 to the second part
I part = II part + 3
The ans 15 is correct
Md. Saifur Rahman said:
1 decade ago
2x+1, 2x+3, 2x+5
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
Santhosh said:
1 decade ago
Rahman is right.
Because the given numbers should be odd numbers.
So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5
Because the given numbers should be odd numbers.
So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5
Swetha said:
1 decade ago
In this problem, they had given three consecutive odd integers.
If we take that 3 odd integers as x , x+2 and x+4,
if we put x = 2 => the numbers will become 2 , 4, 6
these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers?
Can anyone Clear my doubt??
If we take that 3 odd integers as x , x+2 and x+4,
if we put x = 2 => the numbers will become 2 , 4, 6
these nos are even numbers..then how we assume X,X+2,X+4 as three consecutive odd integers?
Can anyone Clear my doubt??
Vamshidhar reddy said:
1 decade ago
Three consecutive integers x, x+1, x+2
3x=2(x+2)+3
x=7
x+2=9
3x=2(x+2)+3
x=7
x+2=9
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