# Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)

2.

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Answer: Option

Explanation:

Let the three integers be *x*, *x* + 2 and *x* + 4.

Then, 3*x* = 2(*x* + 4) + 3 *x* = 11.

Third integer = *x* + 4 = 15.

Video Explanation: https://youtu.be/_77C9YE321Y

Discussion:

74 comments Page 2 of 8.
Sanjay said:
6 years ago

Consecutive mean 1 after one. i.e 1, 3, 5, 7etc.

(1)

Akhilkondaparva said:
8 years ago

Let the three odd integers be x, x + 2 and x + 4.

(Integer = 1, 2 , 3).

If x = 1 then the three integers are 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is.

3 more than (+3) twice the third [2 (x + 4) ] => 3x = 2 (x + 4) + 3x = 11.

Since we got "x", we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 15.

Hope you get this.

(Integer = 1, 2 , 3).

If x = 1 then the three integers are 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is.

3 more than (+3) twice the third [2 (x + 4) ] => 3x = 2 (x + 4) + 3x = 11.

Since we got "x", we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 15.

Hope you get this.

HEMANTH REDDY G said:
9 years ago

3 times of 1st consecutive means 3x.

Twice of 3rd consecutive 2(x+4).

3 more than twice of 3rd consecutive 2(x+4)+3, then.

3x = 2(x+4)+3.

3x-2x = 8+3.

x = 11.

3rd integer is x+4 = 11+4 = 15.

Twice of 3rd consecutive 2(x+4).

3 more than twice of 3rd consecutive 2(x+4)+3, then.

3x = 2(x+4)+3.

3x-2x = 8+3.

x = 11.

3rd integer is x+4 = 11+4 = 15.

Kishan said:
8 years ago

Why we go through option answers.

Three times the first = 3 (first number).

Twice the third one = 2 (third number).

3 more than that = 3 + 2 (third number).

To find the third number;

So, we apply the option a (or) b (or) c (or) d.

The first option is 9 if the third integer is 9 then the three odd numbers are 5, 7, 9.

=>So 3 (5) is not equal to 3 + 2 (9).

Option b = 11.

So, the numbers are 7, 9, 11.

=>3 (7) is not equal to 3 + 2 (11).

So let's try option d = 15.

The three odd numbers 11, 13, 15.

=> 3 (11) is equal to 3 + 2 (15).

So, the answer is 15.

Three times the first = 3 (first number).

Twice the third one = 2 (third number).

3 more than that = 3 + 2 (third number).

To find the third number;

So, we apply the option a (or) b (or) c (or) d.

The first option is 9 if the third integer is 9 then the three odd numbers are 5, 7, 9.

=>So 3 (5) is not equal to 3 + 2 (9).

Option b = 11.

So, the numbers are 7, 9, 11.

=>3 (7) is not equal to 3 + 2 (11).

So let's try option d = 15.

The three odd numbers 11, 13, 15.

=> 3 (11) is equal to 3 + 2 (15).

So, the answer is 15.

RKO said:
8 years ago

0 is an even number, about what basis the given question doesn't take o is let me assume if we take consecutive no i.e. X+0=0, so we took directly "X".

Saksham said:
8 years ago

Answer: 13.

Because 11 + 13 = 24.

9*3 = 27.

27-24 = 3.

Because 11 + 13 = 24.

9*3 = 27.

27-24 = 3.

Sanjay said:
8 years ago

Simple way to solve problem z that, 3 times the x of 3 consecutive integers.

So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.

So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.

Gayathri Ganesan said:
8 years ago

I got idea about this solution. But if we assume the solution by question as,

3 times the x of three consecutive integers whether is my assumption also possible na.

3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.

Anyone can explain my logic please.

3 times the x of three consecutive integers whether is my assumption also possible na.

3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.

Anyone can explain my logic please.

Sony said:
9 years ago

At first three number is x, x+2, x+4 these are three consecutive number.

Then according to question (three times the first of three consecutive odd number) here is our first number is x then,

Our first condition will be 3x----- (1).

And then 3 more than twice the third (there third is x+4).

3 more means 3+, twice means 2.

Then twice of third is 2(x+4).

Then again 3+2(2x+4) -------- (2).

Then from equation first and second we get:

3x = 3+2(x+4).

3x = 3+(2x+8).

3x = 3+2x+8.

3x-2x = 11.

x = 11.

Then our third integer is x+4 ==> 11+4 = 15.

Our third integer is (x+4) = 15.

Then according to question (three times the first of three consecutive odd number) here is our first number is x then,

Our first condition will be 3x----- (1).

And then 3 more than twice the third (there third is x+4).

3 more means 3+, twice means 2.

Then twice of third is 2(x+4).

Then again 3+2(2x+4) -------- (2).

Then from equation first and second we get:

3x = 3+2(x+4).

3x = 3+(2x+8).

3x = 3+2x+8.

3x-2x = 11.

x = 11.

Then our third integer is x+4 ==> 11+4 = 15.

Our third integer is (x+4) = 15.

HYNDAVI said:
9 years ago

But whats the reason to multiply 3 on both sides?

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