Aptitude - Problems on Numbers - Discussion

Anyone can explain this problem? Please anyone help me to solve this problem.

Consecutive mean 1 after one. i.e 1, 3, 5, 7etc.

Simple way to solve problem z that, 3 times the x of 3 consecutive integers.

So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.

Let the three odd integers be x, x + 2 and x + 4.

(we know Integers I = 1, 2, 3, ....).

If x = 1 then,

The three integers are {sub x=1 in x, x + 2 and x + 4. } --> 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is 3 more than (add +3) twice the third [2 (x + 4) ].

=> 3x = 2 (x + 4) + 3,

=> x = 11.

Since we got "x" value, we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 11+ 4 = 15.

Hope you get this.

Answer: 13.

Because 11 + 13 = 24.

9*3 = 27.
27-24 = 3.

0 is an even number, about what basis the given question doesn't take o is let me assume if we take consecutive no i.e. X+0=0, so we took directly "X".

Why we go through option answers.

Three times the first = 3 (first number).
Twice the third one = 2 (third number).
3 more than that = 3 + 2 (third number).

To find the third number;

So, we apply the option a (or) b (or) c (or) d.

The first option is 9 if the third integer is 9 then the three odd numbers are 5, 7, 9.

=>So 3 (5) is not equal to 3 + 2 (9).

Option b = 11.

So, the numbers are 7, 9, 11.

=>3 (7) is not equal to 3 + 2 (11).

So let's try option d = 15.

The three odd numbers 11, 13, 15.

=> 3 (11) is equal to 3 + 2 (15).

So, the answer is 15.

Let the three odd integers be x, x + 2 and x + 4.

(Integer = 1, 2 , 3).

If x = 1 then the three integers are 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is.

3 more than (+3) twice the third [2 (x + 4) ] => 3x = 2 (x + 4) + 3x = 11.

Since we got "x", we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 15.

Hope you get this.

Consecutive means numbers follow in a series or sequence (i.e) each number follow in order.

Ex: consecutive num-1 2 3 4 5 6 7 Etc.
consecutive even num - assume x is even
Then x x+2 x+4 is even
(i.e) x=2 x+2=4 x+4=6
2 4 6 is even
Consecutive odd num - assume x is odd
Then x x+2 x+4 is odd
(i.e) x=1 x+2=3 x+4=5
1 3 5 is odd
Soln.
First three consecutive odd x x+2 x+4
3x=3+(2*(x+4))
x=11
Third num=x+4=11+4=15.

I got idea about this solution. But if we assume the solution by question as,

3 times the x of three consecutive integers whether is my assumption also possible na.

3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.

Anyone can explain my logic please.