Aptitude - Problems on Numbers - Discussion

At first three number is x, x+2, x+4 these are three consecutive number.

Then according to question (three times the first of three consecutive odd number) here is our first number is x then,

Our first condition will be 3x----- (1).

And then 3 more than twice the third (there third is x+4).

3 more means 3+, twice means 2.

Then twice of third is 2(x+4).

Then again 3+2(2x+4) -------- (2).

Then from equation first and second we get:

3x = 3+2(x+4).
3x = 3+(2x+8).

3x = 3+2x+8.
3x-2x = 11.
x = 11.

Then our third integer is x+4 ==> 11+4 = 15.

Our third integer is (x+4) = 15.

But whats the reason to multiply 3 on both sides?

Can any one say how to solve this in 32 seconds?

If you take x+1 as first odd no. Then put 1 in the place of x, it becomes 1+1=2 its not odd integer you got it.

Three consecutive odd numbers x+1, x+3, x+5.

(x+1)+(x+3)+(x+5) = 3+2(x+5).

x = 4. So the third integer x+5 = 4+5 = 9.

I think the answer will be 9 because in this problem three consecutive odd numbers is asked then, how can we start with 0 is my doubt.

Instead of that directly can't we take 1, 3, 5.

Here is the perfect answer.

Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).

Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.

Therefore, 15 is the answer.

Answer can be 11 also !
Suppose 7,9,11 are the hree consecutive odd numbers!

If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.

Zero included in a set of whole numbers. So if we start putting 1, 3, 5 .....in x, we get the consecutive odd numbers only!!

In question written is three consecutive odd integer.

Can, I do like this if I take odd no time two?

3x + 5x + 7x= 15.