Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
76 comments Page 4 of 8.
Megersa said:
8 years ago
Three consecutive integers are: x, x+2 &x+4 but if it says three times the first of three consecutive, it means that 3 (x+x+2+x+4) not 3x, so doing by this method the result becomes negative integer, so by itself, the question has its own problem.
HEMANTH REDDY G said:
1 decade ago
3 times of 1st consecutive means 3x.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
A.M.M said:
8 years ago
Let the three consecutive old numbers be; x+3, x+5, x+7,
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
Sukanya said:
8 years ago
But 2x+1,2x+3,2x+5. are better examples to understand this problem because if we substitute even numbers in x, x+2,x+3 we didn't get odd numbers.
Abinash said:
8 years ago
I could not get how 3X came in the question it is given that 3 times the first three consecutive number what my point is that it should be 3{X (X+2) (X+4) } but why is it 3X?
Kelhen said:
8 years ago
Three consecutive odd integers that's;
X+1, x+3, x+5,
From the question.
3(x+1) = 2(x+5)+3,
3x+3 = 2x+10+3,
X = 10.
Therefore the third integer is;
X+5;
10+5 = 15.
X+1, x+3, x+5,
From the question.
3(x+1) = 2(x+5)+3,
3x+3 = 2x+10+3,
X = 10.
Therefore the third integer is;
X+5;
10+5 = 15.
Chandan kumar said:
8 years ago
Let first consecutive odd integer=x+1,
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
Sandhiya said:
2 months ago
In this question, they have mentioned that three odd integers should be more than twice the third integer, but in simple we can take 3 as mentioned in the question. After three, let's take two more odd numbers 3, 5, 7. When we add all this, we will get an answer of 15.
Vamshidhar reddy said:
1 decade ago
Three consecutive integers x, x+1, x+2
3x=2(x+2)+3
x=7
x+2=9
3x=2(x+2)+3
x=7
x+2=9
Sukruthi said:
1 decade ago
As they hav given 3 consecutive odd integers then that 3 can be assumed as 2x+1,2x+3,2x+5 ...
because x,x+2,x+4 wont give us odd values if v substitute any positive integers. then the values which i have assumed can satisfy all consecutive odd integers so now
1st of 3 consecutive integers is 2x+1
so now 3*(2x+1)=3+(2*(2x+5)
=> 6x+3=4x+13
=> x=5
now 3rd integer is
2x+5
=> 2(5)+5=15.
because x,x+2,x+4 wont give us odd values if v substitute any positive integers. then the values which i have assumed can satisfy all consecutive odd integers so now
1st of 3 consecutive integers is 2x+1
so now 3*(2x+1)=3+(2*(2x+5)
=> 6x+3=4x+13
=> x=5
now 3rd integer is
2x+5
=> 2(5)+5=15.
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