Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 7 of 8.
Utkarsh said:
1 decade ago
If we put x=1,then three consecutive no's x,x+2,x+4 gets an odd no.
Vamshidhar reddy said:
1 decade ago
Three consecutive integers x, x+1, x+2
3x=2(x+2)+3
x=7
x+2=9
3x=2(x+2)+3
x=7
x+2=9
Saksham said:
10 years ago
Answer: 13.
Because 11 + 13 = 24.
9*3 = 27.
27-24 = 3.
Because 11 + 13 = 24.
9*3 = 27.
27-24 = 3.
Md. Saifur Rahman said:
1 decade ago
2x+1, 2x+3, 2x+5
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
3(2x+1)=2(2x+5)+3
... x=5
(2x+5)=15
Sathish said:
1 decade ago
How this 3x = 2(x + 4) + 3 came up, please explain?
HYNDAVI said:
1 decade ago
But whats the reason to multiply 3 on both sides?
Sanjay said:
7 years ago
Consecutive mean 1 after one. i.e 1, 3, 5, 7etc.
(1)
Aandrew said:
1 decade ago
Can any one say how to solve this in 32 seconds?
Swati said:
9 years ago
Instead of that directly can't we take 1, 3, 5.
Pratap said:
6 years ago
X+1, X+3, X+5.
Atq:
3(X+1) = 3+2(X+5),
X = 10.
Atq:
3(X+1) = 3+2(X+5),
X = 10.
(2)
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