Aptitude - Problems on Numbers - Discussion

Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)

Problems on Numbers

Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:

Answer: Option

Explanation:

Let the three integers be x, x + 2 and x + 4.

Then, 3x = 2(x + 4) + 3 x = 11.

Third integer = x + 4 = 15.

Discussion:

75 comments Page 5 of 8.

Santhosh said: 1 decade ago

Rahman is right.

Because the given numbers should be odd numbers.

So we have to take...the three consecutive odd numbers as 2x+1, 2x+3, 2x+5

Cutie said: 1 decade ago

@Muthu the answer is 15 you solved it as 11 this is wrong.

3x = 2(x+4)+3.
3x = 2x+8+3.
3x = 2x+11.
3x-2x = 11.
x = 11.

Like this :).

Kavitha said: 9 years ago

Zero included in a set of whole numbers. So if we start putting 1, 3, 5 .....in x, we get the consecutive odd numbers only!!

Baal said: 8 years ago

In question written is three consecutive odd integer.

Can, I do like this if I take odd no time two?

3x + 5x + 7x= 15.

Nishanthi said: 1 decade ago

Here 3 more than that of the value of x so we use.

3x=2 (x+4) +3, 0 is odd or even number so in this problem 0 is used.

Prashants.s.wagge said: 1 decade ago

Just solve in simp way.

1st 3 odd int are 1, 3, 5.

Add those 1+3+5 = 9.

Now take 3 odd num after 9 i.e. = 15.

Reshma said: 1 decade ago

If you take x+1 as first odd no. Then put 1 in the place of x, it becomes 1+1=2 its not odd integer you got it.

Prerak said: 1 decade ago

Hey can anyone explain this problem? I don't understand these "odd integers is 3 more than twice the third".

Keerthi said: 1 decade ago

How we take x, x+2, x+4 are odd integers if we take x=2 then it become even can any one clear this doubt ?

Govind said: 1 decade ago

Num are 2x+1, 2X+3, 2X+5 then.

3(2X+1) = 2(2x+3)+3.

6x+3 = 4x+6+3.

x = 2.

Third integer: 2x+5 = 9.

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