Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 6 of 8.
Akhilkondaparva said:
9 years ago
Let the three odd integers be x, x + 2 and x + 4.
(we know Integers I = 1, 2, 3, ....).
If x = 1 then,
The three integers are {sub x=1 in x, x + 2 and x + 4. } --> 1, 3, 5 => which are odd.
Three times the first of three consecutive odd integers (Which is 3x) is 3 more than (add +3) twice the third [2 (x + 4) ].
=> 3x = 2 (x + 4) + 3,
=> x = 11.
Since we got "x" value, we have to find the third integer value i.e. x + 4 value.
=> Third integer = x + 4 = 11+ 4 = 15.
Hope you get this.
(we know Integers I = 1, 2, 3, ....).
If x = 1 then,
The three integers are {sub x=1 in x, x + 2 and x + 4. } --> 1, 3, 5 => which are odd.
Three times the first of three consecutive odd integers (Which is 3x) is 3 more than (add +3) twice the third [2 (x + 4) ].
=> 3x = 2 (x + 4) + 3,
=> x = 11.
Since we got "x" value, we have to find the third integer value i.e. x + 4 value.
=> Third integer = x + 4 = 11+ 4 = 15.
Hope you get this.
Swati said:
9 years ago
Instead of that directly can't we take 1, 3, 5.
Vicky said:
9 years ago
Here is the perfect answer.
Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).
Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.
Therefore, 15 is the answer.
Let 3 numbers be x + 1, x + 3, x + 5.
3 (x + 1) = 3 + 2 (x + 5).
Simplify it then you will get x = 5,
Then substitute x in x + 5.
10 + 5 = 15.
Therefore, 15 is the answer.
Mahaprasad said:
9 years ago
Answer can be 11 also !
Suppose 7,9,11 are the hree consecutive odd numbers!
If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.
Suppose 7,9,11 are the hree consecutive odd numbers!
If the first number will be 7. Three times of 7 would be 21!
2 times of second number(9) would be 18.
21 is greater than 18 by 3 number.
So it justifies the equation.
Kavitha said:
9 years ago
Zero included in a set of whole numbers. So if we start putting 1, 3, 5 .....in x, we get the consecutive odd numbers only!!
Baal said:
8 years ago
In question written is three consecutive odd integer.
Can, I do like this if I take odd no time two?
3x + 5x + 7x= 15.
Can, I do like this if I take odd no time two?
3x + 5x + 7x= 15.
Megersa said:
8 years ago
Three consecutive integers are: x, x+2 &x+4 but if it says three times the first of three consecutive, it means that 3 (x+x+2+x+4) not 3x, so doing by this method the result becomes negative integer, so by itself, the question has its own problem.
A.M.M said:
8 years ago
Let the three consecutive old numbers be; x+3, x+5, x+7,
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
3 times the first odd num = 3(x+3).
2 times the third odd num = 2(x+7) +3(which is in the question
3(x+3)=2(x+7)+3,
=3x+9=2x+14+3,
3x-2x=14+3-9,
x = 8.
Now to know what the the third integer is (x+7),
So x =8+7,
=15.
M.Muthumari said:
8 years ago
Consecutive means numbers follow in a series or sequence (i.e) each number follow in order.
Ex: consecutive num-1 2 3 4 5 6 7 Etc.
consecutive even num - assume x is even
Then x x+2 x+4 is even
(i.e) x=2 x+2=4 x+4=6
2 4 6 is even
Consecutive odd num - assume x is odd
Then x x+2 x+4 is odd
(i.e) x=1 x+2=3 x+4=5
1 3 5 is odd
Soln.
First three consecutive odd x x+2 x+4
3x=3+(2*(x+4))
x=11
Third num=x+4=11+4=15.
Ex: consecutive num-1 2 3 4 5 6 7 Etc.
consecutive even num - assume x is even
Then x x+2 x+4 is even
(i.e) x=2 x+2=4 x+4=6
2 4 6 is even
Consecutive odd num - assume x is odd
Then x x+2 x+4 is odd
(i.e) x=1 x+2=3 x+4=5
1 3 5 is odd
Soln.
First three consecutive odd x x+2 x+4
3x=3+(2*(x+4))
x=11
Third num=x+4=11+4=15.
Sukanya said:
8 years ago
But 2x+1,2x+3,2x+5. are better examples to understand this problem because if we substitute even numbers in x, x+2,x+3 we didn't get odd numbers.
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