Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 7 of 8.
Abinash said:
8 years ago
I could not get how 3X came in the question it is given that 3 times the first three consecutive number what my point is that it should be 3{X (X+2) (X+4) } but why is it 3X?
Kelhen said:
7 years ago
Three consecutive odd integers that's;
X+1, x+3, x+5,
From the question.
3(x+1) = 2(x+5)+3,
3x+3 = 2x+10+3,
X = 10.
Therefore the third integer is;
X+5;
10+5 = 15.
X+1, x+3, x+5,
From the question.
3(x+1) = 2(x+5)+3,
3x+3 = 2x+10+3,
X = 10.
Therefore the third integer is;
X+5;
10+5 = 15.
Chandan kumar said:
7 years ago
Let first consecutive odd integer=x+1,
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
second consecutive odd integer= x+3,
Third consecutive odd integer=x+5,
3(x+1)=2(x+5)+3,
3x+3= 2x+10+3,
3x-2x=13-3,
x=10.
Third consecutive odd integer=x+5,
= 10+5,
= 15.
Sanjay said:
7 years ago
Consecutive mean 1 after one. i.e 1, 3, 5, 7etc.
(1)
Ramya said:
7 years ago
Anyone can explain this problem? Please anyone help me to solve this problem.
(2)
Pratap said:
6 years ago
X+1, X+3, X+5.
Atq:
3(X+1) = 3+2(X+5),
X = 10.
Atq:
3(X+1) = 3+2(X+5),
X = 10.
(2)
Shanu kumar said:
6 years ago
Odd numbers are never be in form of x, x+2 etc.
Odd no Is in the form of 2x+1.
Odd no Is in the form of 2x+1.
(3)
Mahin said:
6 years ago
The Consecutive odd integers are (2x+1, 2x+3, 2x+5). Sub any no.for 'x', you'll get an odd integer.
Now, try solving the question with these three, you'll get X = 5;
That means the 3rd integer, 2X + 5 = 15.
Now, try solving the question with these three, you'll get X = 5;
That means the 3rd integer, 2X + 5 = 15.
(3)
Vamsikrishnareddy said:
6 years ago
Anybody can explain short cut of this problem.
(3)
Lavanya said:
5 years ago
Let three consecutive odd integers are: x, x+2,x+4.
Three times the first of three integers, so--> 3x; is 3 more than twice the third so--> 3+ 2(x+4).
Then, we get an equation like 3x=3+2(x+4).
=3+2x+8.
3x-2x=11
X=11.
So, the third integer is x+4=15.
Three times the first of three integers, so--> 3x; is 3 more than twice the third so--> 3+ 2(x+4).
Then, we get an equation like 3x=3+2(x+4).
=3+2x+8.
3x-2x=11
X=11.
So, the third integer is x+4=15.
(9)
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