Aptitude - Problems on Numbers - Discussion

If you take x+1 as first odd no. Then put 1 in the place of x, it becomes 1+1=2 its not odd integer you got it.

Can any one say how to solve this in 32 seconds?

But whats the reason to multiply 3 on both sides?

At first three number is x, x+2, x+4 these are three consecutive number.

Then according to question (three times the first of three consecutive odd number) here is our first number is x then,

Our first condition will be 3x----- (1).

And then 3 more than twice the third (there third is x+4).

3 more means 3+, twice means 2.

Then twice of third is 2(x+4).

Then again 3+2(2x+4) -------- (2).

Then from equation first and second we get:

3x = 3+2(x+4).
3x = 3+(2x+8).

3x = 3+2x+8.
3x-2x = 11.
x = 11.

Then our third integer is x+4 ==> 11+4 = 15.

Our third integer is (x+4) = 15.

I got idea about this solution. But if we assume the solution by question as,

3 times the x of three consecutive integers whether is my assumption also possible na.

3(x+X+2+x+4) = 3+2(x+4) // I consider it for first 3 con int respectively.

Anyone can explain my logic please.

Simple way to solve problem z that, 3 times the x of 3 consecutive integers.

So, he said about odd numbers, now we take 3 consecutive are x, x+2, x+4, then we know odd numbers are 1, 3, 5, 7, 9,... so, take first 3 odd numbers and place like this, x+x+2+x+4, 1+3+2+5+4 = 15.

Answer: 13.

Because 11 + 13 = 24.

9*3 = 27.
27-24 = 3.

0 is an even number, about what basis the given question doesn't take o is let me assume if we take consecutive no i.e. X+0=0, so we took directly "X".

Why we go through option answers.

Three times the first = 3 (first number).
Twice the third one = 2 (third number).
3 more than that = 3 + 2 (third number).

To find the third number;

So, we apply the option a (or) b (or) c (or) d.

The first option is 9 if the third integer is 9 then the three odd numbers are 5, 7, 9.

=>So 3 (5) is not equal to 3 + 2 (9).

Option b = 11.

So, the numbers are 7, 9, 11.

=>3 (7) is not equal to 3 + 2 (11).

So let's try option d = 15.

The three odd numbers 11, 13, 15.

=> 3 (11) is equal to 3 + 2 (15).

So, the answer is 15.

Let the three odd integers be x, x + 2 and x + 4.

(Integer = 1, 2 , 3).

If x = 1 then the three integers are 1, 3, 5 => which are odd.

Three times the first of three consecutive odd integers (Which is 3x) is.

3 more than (+3) twice the third [2 (x + 4) ] => 3x = 2 (x + 4) + 3x = 11.

Since we got "x", we have to find the third integer value i.e. x + 4 value.

=> Third integer = x + 4 = 15.

Hope you get this.