Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 4 of 8.
Sathish said:
1 decade ago
How this 3x = 2(x + 4) + 3 came up, please explain?
Geetha said:
1 decade ago
What they said in question in three consecutive odd numbers, first number 3 times and 2 times of 3 rd number different is 3.
So we can consider that number should be like this.
x, x+2, x+4.
3x-2 (x+4) = 3.
x-8 = 3.
x = 11.
They asked about the third number so it is x+4 = 11+4 = 15.
So we can consider that number should be like this.
x, x+2, x+4.
3x-2 (x+4) = 3.
x-8 = 3.
x = 11.
They asked about the third number so it is x+4 = 11+4 = 15.
Amrith said:
1 decade ago
Three times the first of three consecutive odd integers.
Why is 3x taken didn't get it.
Why is 3x taken didn't get it.
Raj said:
1 decade ago
Any one can explain these problems why we assume the number as X+1, X+2X, X+3?
Prabhu said:
1 decade ago
How will come? please explain. I couldn't understand.
3x = 2(x+4)+3.
3x = 2(x+4)+3.
V.Ranjitha said:
1 decade ago
Hi friends,
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
I think Govind is correct. Because the x value may be odd number or even number.(2x+1,2x+3,2x+5)
If x=0,
We get 1, 3, 5.
If x=1(odd),
We get 3, 5, 7.
If x=2(even),
We get 5, 7, 9.
Ssgm said:
1 decade ago
An integer n any odd will be (2n+1).
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
After (2n+1) is (2n+3) then (2n+5).
From the Q:
3(2n+1) > 2(2n+5).
=> n > 3.5 => n start from 4 to infinity.
So the numbers (2(4)+1=9), 11, 13 and I say the answer is 13.
Neeraj upadhyay said:
1 decade ago
Three consecutive integer are 2x+1, 2x+3, 2x+5.
Now according to question.
3(2x+1) = 2(2x+5)+3.
6x+3 = 4x+10+3.
2x = 10.
x = 5.
And now third number is 2x+5 = 2*5+5 = 15.
15 is a answer.
Now according to question.
3(2x+1) = 2(2x+5)+3.
6x+3 = 4x+10+3.
2x = 10.
x = 5.
And now third number is 2x+5 = 2*5+5 = 15.
15 is a answer.
HEMANTH REDDY G said:
1 decade ago
3 times of 1st consecutive means 3x.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
Twice of 3rd consecutive 2(x+4).
3 more than twice of 3rd consecutive 2(x+4)+3, then.
3x = 2(x+4)+3.
3x-2x = 8+3.
x = 11.
3rd integer is x+4 = 11+4 = 15.
Gayathri said:
1 decade ago
Three consecutive odd numbers x+1, x+3, x+5.
(x+1)+(x+3)+(x+5) = 3+2(x+5).
x = 4. So the third integer x+5 = 4+5 = 9.
I think the answer will be 9 because in this problem three consecutive odd numbers is asked then, how can we start with 0 is my doubt.
(x+1)+(x+3)+(x+5) = 3+2(x+5).
x = 4. So the third integer x+5 = 4+5 = 9.
I think the answer will be 9 because in this problem three consecutive odd numbers is asked then, how can we start with 0 is my doubt.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers