Aptitude - Problems on Numbers - Discussion
Discussion Forum : Problems on Numbers - General Questions (Q.No. 2)
2.
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
Answer: Option
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 
x = 11.
Third integer = x + 4 = 15.
Video Explanation: https://youtu.be/_77C9YE321Y
Discussion:
75 comments Page 3 of 8.
Santhosh said:
1 decade ago
Three consecutive odd integers are x+1, x+3, x+5
So,
3(x+1) = 3+2(x+5).
3x+3 = 3 + 2x + 10.
x = 10. So the third number is x+5.
10+5 = 15.
Answer 15.
So,
3(x+1) = 3+2(x+5).
3x+3 = 3 + 2x + 10.
x = 10. So the third number is x+5.
10+5 = 15.
Answer 15.
Nusohel said:
1 decade ago
Three conservatives odd integers are X, X+2, X+4
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4)
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Kamal said:
1 decade ago
How can we take x, x+2, x+4 as odd positive integers. Kindly clear my doubt?
Nani said:
1 decade ago
If we take three consecutive numbers are x, x+2, x+4....
If we substitute x as 1 (because 1 is the 1st odd num).
We get odd numbers.....1, 3, 5..
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4).
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
If we substitute x as 1 (because 1 is the 1st odd num).
We get odd numbers.....1, 3, 5..
Three times the first of three consecutive odd integers is 3X.
3 more than is 3+
Twice the third is 2(X+4).
3x = 3+2(X+4).
x = 11.
Third integer = x + 4 = 15.
Prashants.s.wagge said:
1 decade ago
Just solve in simp way.
1st 3 odd int are 1, 3, 5.
Add those 1+3+5 = 9.
Now take 3 odd num after 9 i.e. = 15.
1st 3 odd int are 1, 3, 5.
Add those 1+3+5 = 9.
Now take 3 odd num after 9 i.e. = 15.
Govind said:
1 decade ago
Num are 2x+1, 2X+3, 2X+5 then.
3(2X+1) = 2(2x+3)+3.
6x+3 = 4x+6+3.
x = 2.
Third integer: 2x+5 = 9.
3(2X+1) = 2(2x+3)+3.
6x+3 = 4x+6+3.
x = 2.
Third integer: 2x+5 = 9.
Learner said:
1 decade ago
I believe when integers have been mentioned in the question and not positive or negative so better to have them as
2x-1, x, 2x+1.... and then solve the problem.
So the third integer comes out to be 9.
2x-1, x, 2x+1.... and then solve the problem.
So the third integer comes out to be 9.
Muthu said:
1 decade ago
Hi guys. Any one clear my doubt.
3x = 2(x+4)+3.
How can you get above steps ?
3x = 2(x+4)+3.
How can you get above steps ?
Cutie said:
1 decade ago
2x+1, 2x+3, 2x+5 is the correct form.
Cutie said:
1 decade ago
@Muthu the answer is 15 you solved it as 11 this is wrong.
3x = 2(x+4)+3.
3x = 2x+8+3.
3x = 2x+11.
3x-2x = 11.
x = 11.
Like this :).
3x = 2(x+4)+3.
3x = 2x+8+3.
3x = 2x+11.
3x-2x = 11.
x = 11.
Like this :).
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