Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 28)
28.
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:
Answer: Option
Explanation:
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
Discussion:
19 comments Page 2 of 2.
Ambi said:
1 decade ago
Why its not X square? and only X. While solving mathematically it should be x square?
Gufran said:
1 decade ago
Already uttam find....X=8.
and we have 2X&3X=2*8=16 & 3*8=24
and we have 2X&3X=2*8=16 & 3*8=24
Arif said:
1 decade ago
Here you do 2x and 3x. The sum of two. So 2x*3x=6x2. Why 6x?
MENA said:
2 years ago
@ALL.
48/2 = 24,
48/3 = 16,
Then, 24+16 = 40.
Thanks!
48/2 = 24,
48/3 = 16,
Then, 24+16 = 40.
Thanks!
(11)
Rakesh.h said:
9 years ago
Simple way.
48/2 = 24.
48/3 = 16.
24 + 16 = 40.
48/2 = 24.
48/3 = 16.
24 + 16 = 40.
(3)
Aman said:
3 years ago
How the LCM of 2x, 3x = 6x? Explain please.
(1)
Sanjay kiran said:
1 decade ago
How 16 and 24 got? Please explain.
Mythili said:
2 decades ago
How 6x came? please explain.
Ritu said:
1 decade ago
How came 16 and 24 ?
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